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saveliy_v [14]
3 years ago
8

Choose the substance with the lowest vapor pressure at a given temperature.

Chemistry
1 answer:
madam [21]3 years ago
4 0
Vapor pressure is inversely proportional to a substance's boiling point. So it means the one with lowest vapor pressure has the highest boiling point. CO2, BF3, He, and PF5 are non-ionic compounds (not to mention gases) so that they have (somewhat) low boiling points. BeCl2 is the answer because it has the highest boiling point at 482°C .
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The answer is c because ice is cold
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Why did the increase in consumerism occur in the Roaring Twenties?(1 point)
enot [183]

Answer:

A. There were new technologies and new innovations to drive the sale of goods, since people could afford them

Explanation:

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Magnesium (average atomic mass = 24.3050 amu) consists of three isotopes with masses 23.9850 amu, 24.9858 amu, and 25.9826 amu.
iris [78.8K]

Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%

Explanation: Given that the average atomic mass(M) of magnesium

= 24.3050amu

Mass of first isotope (M1) = 23.9850amu

Mass of middle isotope (M2)=24.9858amu

Mass of last isotope(M3)= 25.9826amu

Total abundance = 1

Abundance of middle isotope = 0.10

Let abundance of first and last isotope be x and y respectively.

x+0.10+y =1

x = 0.90-y

M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope

24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y

Substitute x= 0.90-y

Then

y = 0.11

Since y=0.11, then

x= 0.90-0.11

x=0.79

Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%

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3 years ago
The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea
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Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

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Initial concentration of the reactant = x

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Time taken by the sample, t = ?

Formula used :

A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

A_o = initial concentration of reactant

A = concentration of reactant left after the time, (t)

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A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

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