Answer:
9.57 mol.
Explanation:
<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>
<em />
<em>M = (no. of moles of solute)/(V of the solution (L)).</em>
<em></em>
∴ M = (no. of moles of sucrose)/(V of the solution (L)).
1.1 M = (no. of moles of sucrose)/(8.7 L).
<em>∴ no. of moles of sucrose = (1.1 M)(8.7 L) = 9.57 mol.</em>
Answer: A/40 it is actually 39.997 but since that is not an answer they rounded up
Explanation:
When `CO_(2)` is bubbled through a cold pasty solution of barium peroxide in water, `H_(2)O_(2)` is obtained. <br> `BaO+CO_(2)+H_(2)OtoBaCO_(3)+H_(2)O_(2)` Barium carbonate being insoluble is filtered off. This is known as Merck's process.
<h3>What is meant by Perhydrol?</h3>
perhydrol (countable and uncountable, plural perhydrols) A stabilised solution of hydrogen peroxide.
<h3>What is Merck's Perhydrol?</h3>
Uses: Perhydrol is used as an antiseptic for wounds, and also acts as a germicide to kill bacteria and germs.
Being a strong oxidizing agent it has bleaching properties and acts as a ripening agent.
Learn more about merck's process here:
<h3>
brainly.com/question/16856280</h3><h3 /><h3>#SPJ4</h3>
I believe your answer would be helium friend :)
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
