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inysia [295]
3 years ago
5

Q4. The student started with 16.0 grams of NaCl, show the calculation for the percent error that

Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
5 0

Answer:

72.6% Error

Explanation:

% error = \frac{Real-Measured}{Real} * 100

\frac{58.44-16}{58.44} *100= 72.6

58.44 is the weight of NaCl

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sladkih [1.3K]

Answer:

When we cook food in the kitchen, that's the region of higher concentration of the smell. By diffusion, the smell spreads to the whole room and thereby whole house, so anyone standing at a distance, can smell it.

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3 years ago
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Balance and find out the coefficients of reactions and products ​
kolezko [41]

Answer:

2, 1, 1, 4.

Explanation:

Hello there!

In this case, for the given chemical reaction:

H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\

We can see how there is one SO4 on the left and two on the right, thus, we add a 2 in front of H2SO4:

2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+H_2O\\

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2H_2SO_4+Pb(OH)_4\rightarrow Pb(SO_4)_2+4H_2O\\

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6 0
3 years ago
The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
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3 years ago
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Answer:

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