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2 years ago

How many moles of ammonia can be formed from 4.0 mol H2

Chemistry

1 answer:

Bess [88]2 years ago

3 0

Answer: 1. 2.7 moles of ammonia are formed

2. 12.0 moles of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

$N_2+3H_2\rightarrow 2NH_3$

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form = $\frac{2}{3}\times 4.0=2.7moles$ of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by = $\frac{3}{2}\times 8.0=12.0moles$ of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with = $\frac{1}{3}\times 6.0=2.0moles$ of nitrogen

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What is the volume of 8.50 moles of hydrogen gas?

Cerrena [4.2K]

Okay!
8.50molH, represents 8.50 moles of Hydrogen gas!

To convert from moles to volume multiply it by the ratio of L/molH
mol of anything in a conversion problem is always 1 unless you are going to an unknown! Try to memorize this, but the number you always put in for the # of liters in a conversion problem is 22.4L (L is a measure of volume)

8.50molH * (22.4 L/ 1 molH)

190.L of Hydrogen Gas.

Hope that helped!

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3 years ago

Why this chemical equation 3P4 + 10O2 = 4P2O5 + P4 is wrong?

ad-work [718]

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3 years ago

How many moles are in 4.6 x 10^19 atoms? *#27 is the question

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3 years ago

What is the difference between mitosis and meiosis

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2 years ago

Read 2 more answers

What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme

boyakko [2]

Answer: The longest wavelength of light is 656.5 nm

Explanation:

For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.096776\times 10^7m^{-1}$

$n_f$ = Higher energy level = $n_i+1=(2+1)=3$

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

So, $6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm$

Hence, the longest wavelength of light is 656.5 nm

4 0

2 years ago