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marishachu [46]
3 years ago
15

Which pair of statements below is correct? Multiple Choice An octet is formed via ionic bonding when one or more valence electro

ns are transferred from one atom to another. An octet is formed via covalent bonding when valence electrons are shared between atoms. An octet is formed via covalent bonding when one or more valence electrons are transferred from one atom to another. An octet is formed via ionic bonding when valence electrons are shared between atoms. An octet cannot be formed via covalent bonding. An octet is always formed via ionic bonding. An octet cannot be formed via ionic bonding. An octet is always formed via covalent bonding.
Chemistry
2 answers:
slamgirl [31]3 years ago
4 0

Answer:

The first 2 statements are correct.

Explanation:

An octet can be formed by ionic bonding (electron transfer) or by covalent bonding ( sharing electrons).

tresset_1 [31]3 years ago
3 0

Answer:

An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another.

An octet is formed via covalent bonding when valence electrons are shared between atoms.

An octet is always formed via ionic bonding

Explanation:  The essence of bonding is stability. An octet or duplet state is formed when one or more valence electrons are shared. when the electrons are shared, the type of bond formed is a covalent bond. An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another.

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Use pv=nrT


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3 years ago
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Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
A buffer solution is composed of 7.50 mol of acid and 4.75 mol of the conjugate base. If the pKa of the acid is 4.90 , what is t
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Answer:

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Explanation:

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Given:

pKa= 4.90

[conjugate base]= 4.75 mol

[acid]= 7.50 mol

We calculate pH as follows:

pH = 4.90 + log (4.75 mol/7.50 mol) = 4.90 + (-0.20) = 4.70

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2 years ago
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Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin
Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

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initial concentration C₀ = 3.65 mg/L

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t = -4.29/-0.12

t = 35.75 days

3 0
3 years ago
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