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marishachu [46]
3 years ago
15

Which pair of statements below is correct? Multiple Choice An octet is formed via ionic bonding when one or more valence electro

ns are transferred from one atom to another. An octet is formed via covalent bonding when valence electrons are shared between atoms. An octet is formed via covalent bonding when one or more valence electrons are transferred from one atom to another. An octet is formed via ionic bonding when valence electrons are shared between atoms. An octet cannot be formed via covalent bonding. An octet is always formed via ionic bonding. An octet cannot be formed via ionic bonding. An octet is always formed via covalent bonding.
Chemistry
2 answers:
slamgirl [31]3 years ago
4 0

Answer:

The first 2 statements are correct.

Explanation:

An octet can be formed by ionic bonding (electron transfer) or by covalent bonding ( sharing electrons).

tresset_1 [31]3 years ago
3 0

Answer:

An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another.

An octet is formed via covalent bonding when valence electrons are shared between atoms.

An octet is always formed via ionic bonding

Explanation:  The essence of bonding is stability. An octet or duplet state is formed when one or more valence electrons are shared. when the electrons are shared, the type of bond formed is a covalent bond. An octet is formed via ionic bonding when one or more valence electrons are transferred from one atom to another.

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Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t
marissa [1.9K]

Answer:

Sample A is a mixture

Sample B is a mixture

Explanation:

For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.

For sample B, we are told that boiling started at 66.2°C and continued until 76.0°C. The implication of this is that B must be a mixture since it boils over a range of temperatures. Pure substances have a sharp boiling point.

7 0
2 years ago
Neutralizing an olympic size swimming pool is conceptually very similar to performaing a massive titration experiment. Suppose a
MrRissso [65]

Answer:

6,97x10⁻³ gallons

Explanation:

pH is defined as:

pH = -log [H⁺]

Thus, you need to have, in the end:

10⁻⁷ = [H⁺]

And you have, in the first:

10^{-9,33} = [H⁺]

The volume of swimming pool is:

700'000 galllons ×\frac{3,78541 L}{1 gallon} = 2649787 L

Thus, the moles of H⁺ in the first and in the end are:

First:

10^{-9,33}mol/L × 2649787L = 1,24x10⁻³ moles

End:

10^{-7}mol/L × 2649787L = 0,265 moles

Thus, the moles of H⁺ you need to add are:

0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>

These moles comes from 10M HCl, thus, the volume in gallons you need to add are:

0,26376moles*\frac{1L}{10moles}* \frac{1gallon}{3,78541L} =

<em>6,97x10⁻³ gallons</em>

<em></em>

I hope it helps!

7 0
4 years ago
How do you do this? very confused
Vlad [161]
The problem you have written you almost have it solved.  Take the moles that you have calculated and multiply that by the molecular weight to get the grams.

The STP problem:
use the moles you calculated along with 1 atm for Pressure, and 273 for the temperature and plug into the PV = nRT equation.  (also use 0.0821 for R)

From there you can solve for the volume

Hope this helps!
4 0
3 years ago
What kind of oxide is formed when a piece of sodium is dropped in the water
aleksley [76]

Answer:

Sodium oxide is the product

Explanation:

4Na+O2->2Na2O

7 0
3 years ago
The reaction described in Part A required 3.40 L of sodium chloride. What is the concentration of this sodium chloride solution
Mumz [18]

Answer:

Part A:

First, convert molarity to moles by multiplying by the volume:

0.293 M AgNO3 = (0.293 moles AgNO3)/1 L x 1.19 L = 0.349 moles AgNO3

5 0
3 years ago
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