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disa [49]
3 years ago
15

During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed

v0 = 28 m/s at an angle θ = 21° above horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Air resistance may be ignored throughout this problem.

Physics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

Detailed solution is given below:

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How does the nuclear charge relate to the energy of the 1s orbital?
nlexa [21]

Explanation:

Effective nuclear charge is defined as he net positive charge experienced by an electron in an atom. It is termed "effective" because the shielding effect of electrons prevents higher orbital electrons from experiencing the full nuclear charge of the nucleus due to the repelling effect of inner-layer electrons.

The 1s is the closest shell to the nucleus of an therefore maximum nuclear charge is experienced. The formula for effective nuclear charge is:

Zeff = Z – S

where

Z = the number of protons in the nucleus, and

S = the shielding constant, the average number of electrons between the nucleus and the electron.

Hence, the energy required to remove an electron from the 1s orbital is the strongest.

3 0
4 years ago
Mass and weight are the same in<br> meaning and unit.<br><br> true or false
schepotkina [342]

Answer:

False.

Explanation:

Mass is how much space an object takes up, while weight is how light or heavy an object is.

4 0
3 years ago
A glass plate 2.95 mmmm thick, with an index of refraction of 1.60, is placed between a point source of light with wavelength 60
Valentin [98]

Answer:

N_T=2086285.67

Explanation:

Given;

Thickness of the glass plate, x=2.95\times 10^{-3}\ m

refractive index of the glass plate, n=1.6

wavelength of light source in vacuum, \lambda=600\times 10^{-9}\ m

distance between the source and the screen, d=1.25\ m

Distance travelled by the light from source to screen in vacuum:

d_v=d-x

d_v=1.25-0.00295

d_v=1.24705\ m

So the no. of wavelengths in the vacuum:

N=\frac{d_v}{\lambda}

N=\frac{1.24705}{6\times 10^{-7}}

N\approx2.0784\times 10^{6}  .......................(1)

<u>Now we find the wavelength of the light wave in the glass:</u>

n=\frac{\lambda}{\lambda'}

where:

\lambda'= wavelength of light in the medium of glass.

1.6=\frac{600\times 10^{-9}}{\lambda'}

\lambda'=375\times 10^{-9}\ m=375\ nm

Now the no. of wavelengths in the glass:

N'=\frac{x}{\lambda'}

N'=\frac{2.95\times 10^{-3}}{375\times 10^{-9}}

N'=7.8667\times 10^{3} ............................(2)

From (1) & (2):

  • total no. of wavelengths are there between the source and the screen:

N_T=N+N'

N_T=2086285.67

5 0
3 years ago
What is the answer to this​
umka2103 [35]
It’s the atomic mass
3 0
3 years ago
Megan walks 1100 m to the left in 330s. What was her average speed in m/s?
Hunter-Best [27]

Answer:

3.33m/s

Explanation:

Speed is the change in distance of a body with respect to time.

Speed = Distance/Time

Given

Distance = 1100m

Time = 330s

Speed = 1100/330

Speed = 3.33m/s

Hence her average speed in m/s is 3.33m/s

7 0
4 years ago
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