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3 years ago

A man hits a golf ball (0.2 kg) which accelerates at a rate of 20 m/s2. What amount of force acted on the ball?

1 answer:

4 0

Newton taught us that Force = (mass) x (acceleration)

Force = (0.2) x (20) = <em>4 newtons</em> .

Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.

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When you hammer a nail into wood, the nail heats up. 30 Joules of energy was absorbed by a 5-g nail as it was hammered into plac

Goryan [66]

Answer:

13.33 K

Explanation:

Given that,

Heat absorbed, Q = 30 J

Mass of nail, m = 5 g = 0.005 kg

The specific heat capacity of the nail is 450 J/kg-°C.

We need to find the increase in the temperature during the process. The heat absorbed in a process is as follows:

$Q=mc\Delta T\\\\\Delta T=\dfrac{Q}{mc}\\\\\Delta T=\dfrac{30}{0.005\times 450}\\\\=13.33\ K$

So, the increase in temperature is 13.33 K.

7 0

3 years ago

The radius of a small ball is around 3.79747 cm. The radius of a basketball is about 3.16 times larger. What is the ratio of the

Svetradugi [14.3K]

Explanation:

The ratio of the areas is the square of the ratio of the radii.

A/A = 3.16² = 9.99

The ratio of the volumes is the cube of the ratio of the radii.

V/V = 3.16³ = 31.6

3 0

3 years ago

Electric fish generate current with biological cells called electroplaques, which are physiological emf devices. The electroplaq

Harlamova29_29 [7]

Answer:

current in water = 0.924 A

Explanation:

Let the current in each row be i.

Thus, current in water is contributed by each row and total current in water becomes 140i.

We are given;

emf of each electroplaque = 0.15 V

Number of electroplaques = 5000

internal resistance = 0.25 Ω

resistance = 800Ω

Applying Kirchoff's Voltage Law to row and water, we have;

5000E − (5000r)i − 800(140i) = 0

Rearranging;

5000E = (5000r)i + 800(140i)

Plugging in the relevant values;

5000 x 0.15 = i((5000 x 0.25) + 112,000)

750 = 113,250i

i = 750/113,250

i = 0.0066 A

Recall earlier, the current in water is 140i.

Thus, current in water = 140 x 0.0066

= 0.924

5 0

3 years ago

what is the amplitude and wavelength of the wave shown below? A. Amplitude: 15 cm; wavelength: 150 cm B. Amplitude: 30 cm; wavel

ehidna [41]

I would say C...............

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3 years ago

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irina [24]

Answer:

Explanation:

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3 years ago