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MrRa [10]
3 years ago
11

Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters

Mathematics
1 answer:
kondaur [170]3 years ago
8 0
You can solve this by finding all of the factors of 28 and seeing which ones add up to 22 when doubled.

The factors of 28 are as follows:

28 x 1      28(2) + 1(2) = 56 + 2 = 58 ≠ 22
14 x 2      14(2) + 2(2) = 28 + 4 = 32 ≠ 22
 7 x 4         7(2) + 4(2) = 14 + 8 = 22

The dimensions of the rectangle are 4 x 7.


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