Find the dimensions of a rectangle whose perimeter is 22 meters and whose area is 28 square meters
1 answer:
You can solve this by finding all of the factors of 28 and seeing which ones add up to 22 when doubled.
The factors of 28 are as follows:
28 x 1 28(2) + 1(2) = 56 + 2 = 58 ≠ 22
14 x 2 14(2) + 2(2) = 28 + 4 = 32 ≠ 22
7 x 4 7(2) + 4(2) = 14 + 8 = 22
The dimensions of the rectangle are 4 x 7.
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Answer: (2,7)
Midpoint formula = (
,
)
1 + 3 / 2 = 2
5 + 9 / 2 = 7
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Answer : I think 3rd is the answer
Answer:
3
Step-by-step explanation:
3 squared is 9. 5 squared is 25. 25 + 9 = 34. 5 + 3 = 8. So the smaller number is 3.
