Given:
The data values are
11, 12, 10, 7, 9, 18
To find:
The median, lowest value, greatest value, lower quartile, upper quartile, interquartile range.
Solution:
We have,
11, 12, 10, 7, 9, 18
Arrange the data values in ascending order.
7, 9, 10, 11, 12, 18
Divide the data in two equal parts.
(7, 9, 10), (11, 12, 18)
Divide each parenthesis in 2 equal parts.
(7), 9, (10), (11), 12, (18)
Now,
Median = 
= 
= 
Lowest value = 7
Greatest value = 18
Lower quartile = 9
Upper quartile = 12
Interquartile range (IQR) = Upper quartile - Lower quartile
= 12 - 9
= 3
Therefore, median is 10.5, lowest value is 7, greatest value is 18, lower quartile 9, upper quartile 12 and interquartile range is 3.
I believe the answer would be 300. One eighth of the class would be 100 and 1/2 of the class would be 400. 800-(400+100)=300. Hope this helped!
The correct graph to the inequality is a number line with open dot at <em>negative 3</em> with shading to the left and an open dot at 6 with shading to the right. The correct option is the second option
<h3>Linear Inequalities </h3>
From the question, we are to determine the graph for the given compound inequality
The given compound inequality is
4p + 1 < −11 or 6p + 3 > 39
Solve the inequalities separately
4p + 1 < −11
4p < -11 - 1
4p < -12
p < -12/4
p < -3
OR
6p + 3 > 39
6p > 39 - 3
6p > 36
p > 36/6
p > 6
Thus,
p < -3 OR p > 6
Hence, the correct graph to the inequality is a number line with open dot at <em>negative 3</em> with shading to the left and an open dot at 6 with shading to the right. The correct option is the second option
Learn more on Linear Inequalities here: brainly.com/question/5994230
#SPJ1
2800 ÷ 400
Cross out 2 zeros from both numbers, then you have 28 ÷ 4 = 7
1/125 in a decimal is 0.008.
