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Evgen [1.6K]
2 years ago
14

How many grams of ethylene glycol (c2h6o2 must be added to 1.25 kg of water to produce a solution that freezes at -5.88 ∘c?

Chemistry
1 answer:
e-lub [12.9K]2 years ago
6 0
The freezing point depression is calculated through the equation,
                                    ΔT = (kf)  x m 
where ΔT is the difference in temperature, kf is the freezing point depression constant (1.86°C/m), and m is the molality. Substituting the known values,
                                   5.88 = (1.86)(m)
m is equal to 3.16m

Recall that molality is calculated through the equation,
                                  molality = number of mols / kg of solvent
                                       number of mols = (3.16)(1.25) = 3.95 moles
Then, we multiply the calculated amount in moles with the molar mass of ethylene glycol and the answer would be 244.9 g.

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Which of the following has a mass of 10.0 g?
Serjik [45]

Answer:

a.  0.119mol Kr

Explanation:

To solve this problem, we must understand that;

     Mass  = number of moles x molar mass

Molar mass of Kr  = 83.3g/mol

                        Ar = 40g/mol

                        He = 4g/mol

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a0.119 mol Kr               mass  = 0.119 x 83.3 = 9.9g

b 0.400 mol Ar             mass  = 0.4 x 40  = 16g

C 1.25 mol He               mass  = 1.25 x 4  = 5g

d 2.02 mol Ne              mass  = 2.02 x 20.18  = 40.8

Krypton is the answer

5 0
2 years ago
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What is the empirical formula for a compound if a sample contains 1. 0 g of S and 1. 5 g of O? SO SO3 S2O2 S2O3.
Tcecarenko [31]

The empirical formula of the given compound is \bold{SO_3}.

The correct option is B.

<h3>What is an empirical formula?</h3>

The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.

Given,

1.0 g of S

1.5 g of O

To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.

For sulfur

\bold{\dfrac{1.0}{32} =0.03125\; mol}

For oxygen

\bold{\dfrac{1.5}{16} =0.09375\; mol}

Now, divide the greater value of mole came by the smaller value

\bold{\dfrac{0.09375\; mol}{0.03125\;mol} = 3}

Thus, the empirical formula for the given compound is 1 for S and 3 for O

\bold{SO_3}

Learn more about empirical formula, here:

brainly.com/question/11588623

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2 years ago
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