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Anestetic [448]
3 years ago
5

What graph would best represent acceleration as a function of mass when a constant force is applied?

Physics
1 answer:
Alex17521 [72]3 years ago
6 0

The graphs of the acceleration as a function of mass and of the acceleration as a function of force are in attachment.

Explanation:

To answer both parts of the question, we refer to Newton's second law, which states that:

F=ma

where

F is the net force on an object

m is the mass of the object

a is its acceleration

a)

To answer this part, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Therefore, we notice that if a constant force is applied, the acceleration is inversely proportional to the mass of the object:

a \propto \frac{1}{m}

this means that if the mass increases, the acceleration decreases, and if the mass decreases, the acceleration increases.

In a graph of acceleration vs mass, the curve representing this relationship would be a hyperbole. The graph is shown as the first graph in the attached picture.

b)

As before, we re-arrange the previous equation as follows:

a=\frac{F}{m}

Here we notice that if the object has a constant mass, the acceleration is directly proportional to the force applied on the object:

a \propto F

this means that when the force increases, the acceleration increases, and when the force decreases, the acceleration decreases.

In a graph of acceleration vs force, the curve representing this relationship would be a straight line, as shown in the second graph in the attached picture.

Learn more about Newton's second law of motion here:

brainly.com/question/3820012

#LearnwithBrainly

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Objects a and b each have a mass of 25 kilograms. object a has a velocity of 5.98 meters/second. object b is stationary. they un
mash [69]

The total kinetic energy of the system after collision is 223.5J

In elastic collision kinetic energy and momentum are conserved.

According to the question

               mass of object a = 25kg

               mass of object b =  25 kg

        initial velocity of a u1 = 5.98 m/s

        initial velocity  of b u2 = 0

so from momentum conservation-

       mau1 + mbu2 = (m1+m2)v

       25kg × 5.98m/s + 25×0 = (25+25)v

              v = 2.99 m/s

Now the total kinetic energy after the collision will be:

          final kinetic energy = 1/2 (m1+m2) v²

                                           = 1/2 (25+25)× (2.99)²

                                           = 223.5 J

    Thus, total kinetic energy of the system after collision is 223.5J

Learn more about elastic collision here:

  brainly.com/question/1808045

    #SPJ4

7 0
2 years ago
What is my purpose?
castortr0y [4]
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At the top of a roller-coaster, you feel like you might fly off the ride. This is because
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B.??????? 
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3 years ago
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A man travels 25 kilometers in 15 minutes. A police officer stops him and
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Answer:

yes

Explanation:

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15=25

15x4=60 25x4=100

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6 0
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