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Airida [17]
3 years ago
7

What would be the MOLARITY (M) of the NaBr in the same buffer solution, if its concentration is now 0.9% (w/v)?

Chemistry
1 answer:
IRINA_888 [86]3 years ago
6 0
If by buffer solution you mean, a solution of the same concentration, the molarity (M) would stay the same. You would just have a greater volume.
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What is the molarity of a hydrochloric acid solution, when 30.0 mL is neutralized by 48.0 mL of 0.100 mol/L
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The molarity of a hydrochloric acid solution : 0.32 M

<h3>Further explanation  </h3>

Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution).

Titrations can be distinguished including acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases is used.  

Acid-base titration formula  

Ma. Va. na = Mb. Vb. nb  

Ma, Mb = acid base concentration  

Va, Vb = acid base volume  

na, nb = acid base valence  

1 ⇒HCl (valence=1, HCl ⇒H⁺+Cl⁻, one H⁺)

2⇒Ca(OH)₂(valence=2, Ca(OH)₂⇒Ca²⁺+2OH⁻, two OH⁻)

M₂=0.1 M

V₂=48 ml=0.048 L

V₁=30 ml=0.03 L

\tt M_1.V_1.n_1=M_2.V_2.n_2\\\\M_1\times 0.03\times 1=0.1\times 0.048\times 2\\\\M_1=0.32

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(hope this helps ^^)

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