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alexdok [17]
2 years ago
7

Anatom of an element has no electron,will that atom have any mass or not? Can antom exist

Chemistry
1 answer:
densk [106]2 years ago
5 0

Answer:

<em>Generally, all atoms of elements contain three sub-atomic particles- </em><em>Protons</em><em>(Positively-charged), </em><em>Neutrons</em><em>(Neutral) and </em><em>Electrons</em><em>(Negatively-charged)</em><em>. </em>

<em>The Magnitude of the Positive Charge possessed by the Protons and the Magnitude of the Negative Charge possessed by the Electrons cancel each other, which make the atom electrically neutral. </em>

<em>Hence,</em>

<em>Without any electrons, the magnitude of the positive and negative charges wouldn't balance, and the atom would be unstable and disintegrate almost immediately. Hence, all stable atoms should have electrons revolving around them, where the number of protons and electrons are the same, under normal conditions.</em>

<em>To Conclude,</em>

<em>Every atom of an element will have electrons arranged in different shells, or matter couldn't exist without electrons.</em>

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For the neutralization reaction involving hno3 and ca(oh)2, how many liters of 1. 55 m hno3 are needed to react with 45. 8 ml of
Agata [3.3K]

For the neutralization reaction involving HNO₃ and Ca(OH)₂, liters of 1.55 M HNO₃ are needed to react with 45.8 ml of a 4.66 m Ca(OH)₂ solution is 0.270 L.

<h3>What is neutralization reaction?</h3>

Those reactions in which acids and bases will combine with each other for the formation of water molecule and salt, is known as neutralization reaction.

Given chemical reaction is:

2HNO₃ + Ca(OH)₂ → 2H₂O + Ca(NO₃)₂

Moles (n) of Ca(OH)₂ will be calculated by using the below formula:
M = n/V, where

M = molarity = 4.66M

V = volume = 45.8 mL = 0.045 L

n = (4.66)(0.045) = 0.2097 mol

From the stoichiometry of the reaction,

1 mole of Ca(OH)₂ = reacts with 2 moles of HNO₃

0.2097 mole of Ca(OH)₂ = reacts with 2×0.2097=0.419 moles of HNO₃

Again by using the molarity equation volume will be calculated for HNO₃ as:

V = (0.419) / (1.55) = 0.270 L

Hence required volume of HNO₃ is 0.270 L.

To know more about neutralization reaction, visit the below link:

brainly.com/question/23008798

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A sample of argon initially has a volume of 5.0 L and the pressure is 2 atm. If the final temperature is 30° C, the final volume
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We have that every gas satisfies the fundamental gas equation, PV=nRT where P is the Pressure, V is the volume of the gas, n are the moles of the gas, R is a universal constant and T is the Temperature in Kelvin. We have that PV/T=nR and during our process, the moles of the gas do not change (no argon enters or escapes our sample). See attached.

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