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wolverine [178]
4 years ago
5

An empirical formula:__________ 1. gives the relative number of ions of each element per formula unit. 2. gives the number of io

ns of each element per formula unit. 3. uses lines to represent covalent bonds and shows how atoms in a molecule connect or bond to each other. 4. gives the relative number of atoms of each element per formula unit.5. gives the actual number of atoms of each element per formula unit.
Chemistry
1 answer:
crimeas [40]4 years ago
8 0

Answer:

4.  gives the relative number of atoms of each element per formula unit

Explanation:

An empirical formula -

It refers to the formula which determined the simplest whole - number ratio of all the atoms in a given species , is referred to as an empirical formula .

In simple terms ,

It is he smallest formula of the whole number which when multiplied by some whole number gives the actual structure of the compound .

Hence , from the given information of the question ,

The correct option for empirical formula is 4.

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V1T2 = V2T1 is an expression of who’s law
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<u>Answer:</u>

It is the expression of Charles' Law.

<u>Explanation:</u>

The given expression V1T2 = V2T1 is the formula for the Charles' Law.

A special case of an ideal gas is named as the Charles' Law. This law applies to ideal gases only which are at constant pressure.

According to this law, the volume of a fixed mass of a gas is directly proportional to its temperature and is given by:

V1T2 = V2T1

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fenix001 [56]
Step 1: Write the unbalanced equation,

                                 C₂H₆  +  O₂    →    CO₂  +  H₂<span>O

There are 2 C at left hand side and 1 carbon at right hand side. So, multiply CO</span>₂ by 2 to balance C atoms at both side. So,

                                 C₂H₆  +  O₂    →   2 CO₂  +  H₂O

Now, count number of H atoms at both sides. There are 6 H atoms at left hand side and 2 at right hand side. Multiply H₂O by 3 to balance H atoms.


                                 C₂H₆  +  O₂    →   2 CO₂  +  3 H₂O

At last, balance O atoms. There are 2 O atoms at left hand side and 3 O atoms at right hand side. Multiply O₂ with 1.5 (i.e. 3/2) to balance O atoms. i.e.

                                 C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O

Hence, the equation is balanced. If you want to make equation fraction free then multiply all equation with 2. i.e.

                           ( C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O ) × 2

                                2 C₂H₆  +  3 O₂    →   4 CO₂  +  6 H₂O
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