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FromTheMoon [43]
4 years ago
15

A baseball team won 10 games and lost 7 games.approximately what percent of games did the team win?

Mathematics
1 answer:
Afina-wow [57]4 years ago
8 0
7/10

7divide 10 = 0.7

0.7•100=70%

70% is your answer
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I need help please.
skelet666 [1.2K]

Answer:

Step-by-step explanation:

(x²-6x-3)(7x²-4x+7)= ?

Multiply each term of 2nd bracket with the 1st bracket:

=7x²(x²-6x-3) -4x(x²-6x-3) +7(x²-6x-3)

=7x^4-42x^3-21x^2-4x^3+24x^2+12x+7x^2-42x-21

Now solve the like terms:

=7x^4-46x^3+10x^2-30x-21

Therefore the answer is (x²-6x-3)(7x²-4x+7)=7x^4-46x^3+10x^2-30x-21 ....

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4 years ago
What is the relationship between the circumference of a circle and its diameter?
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The answer is A to the question
5 0
3 years ago
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Re-write 15/9 as a mixed number
Y_Kistochka [10]

Answer:

1 6/9

Step-by-step explanation:

3 0
3 years ago
Luke wants to reduce the area of his rectangular garden by one-fourth. The expression 1/4 lw can be used to represent this chang
Leya [2.2K]

Answer:

lw/4

Step-by-step explanation:

Area of a rectangle = length × width

= l × w

Area of a rectangle = let

reduce the area of his rectangular garden by one-fourth

= 1/4 * lw

= 1/4lw

What is another way to write this expression?

Another way to write the expression is

= 1/4 * lw

= lw / 4

3 0
3 years ago
The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se
Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

8 0
3 years ago
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