I will answer this question to the best of my ability, because you have not provided a value of x to plug in.

UW is always equal to 9x-9 or 9(x-1) whenever x is a real number. By plugging in x, we can get the value. For example, if x was 4, we plug in x, giving us 9*4-9=36-9=27 units or 9(4-1)=9(3)=27 units
Don't forget to include units when you complete your answer!

Hope this helps! I did as much as I could!

5 0

3 years ago

PLS HELP WILL MARK AS BRAINLIEST

soldier1979 [14.2K]

Answer:

26. the y intercept is -6

27. the y intercept is 2

28. the y intercept is -3

29. I cant answer because it is cut off in the picture...

Step-by-step explanation:

These equations follow a simple formula- the slope formula

y=mx+b

In this formula:

b is the y intercept

m is the slope that is multiplied by x

hope this helps:)

please crown me brainliest!!!

3 0

2 years ago

The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation

MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

$\bar x = \frac{\sum_{i=1}^n X_i}{n}$

And the population mean is given by:

$\mu= \frac{\sum_{i=1}^n X_i}{N}$

The population variance is defined by:

$\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}$

And the sample variance is defined as:

$s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}$

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is $\sigma=2$ then the variance would be $\sigma^2 = 4$ and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is $\sigma=0.1$ then the variance would be $\sigma^2 = 0.01$ and as we can see is lower than the standard deviation

7 0

3 years ago

What is the one-hundredth term in the sequence 14, 19, 24, 29, 34…?

anzhelika [568]

Rule: look at the sequence. It has the last number as 4 then 9 then for. 4 for odd numbers(odd term numbers like number 3,5 so on) so the last number of the 100 term is 9. It’s 509.

8 0

2 years ago