We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.
Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)
![\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%5B2%28x%2B1%29%5D-%5Cfrac%7B2%7D%7Bx%2B1%7D%5B2%28x%2B1%29%5D%20%3D%201%5B2%28x%2B1%29%5D)
Then shorten the fractions.
![\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%5B2%28x%2B1%29%5D-%5Cfrac%7B2%7D%7Bx%2B1%7D%5B2%28x%2B1%29%5D%20%3D%201%5B2%28x%2B1%29%5D%5C%5Cx%28x%2B1%29-2%282%29%3D1%282x%2B2%29)
Distribute in all.
We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.
We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)
Thus, the answer is x = 3, -2
A; the coordinates in that point make M equidistant from H and F.
23. Kim and Jay leave at the same time to travel 25 miles going to the beach.
Kim drives 9 miles in 12 minutes
Jay drives 10 miles in 15 minutes.
Question: who will arrive first?
Unit rate of Kim
=> 9 miles in 12 minutes
=> 0.75 miles / minutes
=> 25 / 0.75
It will take 33.33 minutes for Kim to arrive
Unit rate of Jay
10 miles in 15 minutes.
=> 10 miles /15 minutes
=> 0.67 miles /minute
=> 25 / 0.67
It will take Jay 37.31 minutes to arrive at the beach.
SO Kim will arrive first
greatest common factor=gcf
least common multule=lcm
with 12 and 16
factors of 12=2 times 2 times 3
factors of 16=2 times 2 times 2 times 2
greates common factor is 2 times 2=4
least common multiple means all factors combined minus repeats or 2 times 2 times 2 times 2 time 3=48
7/10x - 5 = 1/2x
7/10x - 1/2x = 5
7/10x - 5/10x = 5
2/10x = 5
x = 5 / (2/10)
x = 5 * 10/2
x = 50/2
x = 25 gallons <===
