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Troyanec [42]
4 years ago
12

Why are heat transfers associated with phase changes known as latent or "hidden" heats?

Physics
1 answer:
pshichka [43]4 years ago
4 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

Heat transfers associated with phase changes known as latent or "hidden" heats because h<span>eat absorbed or released in a phase change is measured in kJ while temperature is measured in °C.</span>


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A charge of 4.5 × 10-5 C is placed in an electric field with a strength of 2.0 × 104 . If the charge is 0.030 m from the source
ololo11 [35]

Answer:

0.027 J

Explanation:

The formula of the potential energy in electrostatic (U) is

U = q \times E \times d

The values given in the question are

Charge : q = 4.5 \times 10^{-5} C

Electric Field strength : E = 2.0 \times 10^{4} N/C

Distance : d  is 0.030 m

Insert in the formula , will give us

U = 4.5 \times 10^{-5} C \times 2.0 \times 10^{4} N/C \times 0.030 m

Further solving it

U = 0.027 J

Which is the required answer.

Thanks

5 0
3 years ago
Small, slowly moving spherical particles experience a drag force given by Stokes' law: Fd = 6πηrv where r is the radius of the p
Dominik [7]

Answer:

Explanation:

At the time of a body achieving terminal velocity, the drag force becomes equal to the weight of the body less the buoyant force by the surrounding medium which can be represented by the following equation

\frac{4\pi\times r^3(d-\rho)}{3} =6\pi\times n\times r\times v

Where r is radius of the body , d is density of the material of the body σ is density of the medium and n is coefficient of viscosity of the medium and v is terminal velocity.

Simplifying

v = \frac{2\times r^2(d-\rho)}{9\times n}

Assuming the value of density of air as 1.225 kg/m³ and putting other given values in the formula we get

v = [tex]\frac{2\times (1.2\times10^{-5})^2(2182-1.225)}{9\times 1.8\times10^{-5}}[/tex]

v = 387 x 10⁻⁵ m/s

Terminal velocity = 387 x 10⁻⁵ m/s

Time taken to fall a distance of 100 m

= \frac{100}{387\times10^{-5}}

= 2.6 x 10⁴ s.

5 0
3 years ago
You are doing an experiment to determine how many passengers would fit into a full-sized plane. If a scale model plane has space
romanna [79]
The real place should theoretically have space for 87 passengers if it is an exact model and doesn't have modifications in the seat numbers.
5 0
4 years ago
Read 2 more answers
A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with
lord [1]
Momentum, p = m.v
m of the girl = 60.0 kg
m of the boat = 180 kg
v of the girl = 4.0 m/s

A) Momentum of the girl as she is diving:
p = m.v = 60.0 kg * 4.0 m/s = 24.0 N/s

B) momentum of the raft = - momentum of the girl = -24.0 N/s

C) speed of the raft

p = m.v ; v = p/m = 24.0N/s / 180 kg = -0.13 m/s [i.e. in the opposite direction of the girl's velocity]
6 0
3 years ago
A driver brings a car to a full stop in 2.0 s. If the car was
Dvinal [7]
Working displayed in the picture below, the answer is -11 m s^-2

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3 years ago
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