Answer:
Explanation:
Moving a magnet might cause a change in the magnetic field going through the solenoid. Whether or not it will change depends on the movement.
According to Faraday's law of induction a voltage is induced in a coil by a change in the magnetic flux. Magnetic flux is defined as the dot product of the magnetic field (a vector field) by the area enclosed by a loop of the coil.
The voltage is induced by the variation of the magnetic flux:
Where
ε: electromotive fore
N: number of turns in the coil
ΦB: magnetic flux
Moving the magnet faster would increase the rare of change of the magnetic flux, resulting in higher induced voltage.
Turning the magnet upside down would invert the direction of the magnetic field, reversing the voltage induced.
Answer:
Explanation:
Let the magnitude of magnetic field be B .
flux passing through the coil's = area of coil x field x no of turns
Φ = 3.13 x 10⁻⁴ x B x 135 = 422.55 x 10⁻⁴ B .
emf induced = dΦ / dt , Φ is magnetic flux.
current i = dΦ /dt x 1/R
charge through the coil = ∫ i dt
= ∫ dΦ /dt x 1/R dt
= 1 / R ∫ dΦ
= Φ / R
Total resistance R = 61.1 + 44.4 = 105.5 ohm .
3.44 x 10⁻⁵ = 422.55 x 10⁻⁴ B / 105.5
B = 3.44 x 10⁻⁵ x 105.5 / 422.55 x 10⁻⁴
= .86 x 10⁻¹
= .086 T .
Answer:
K = 80.75 MeV
Explanation:
To calculate the kinetic energy of the antiproton we need to use conservation of energy:
<em>where 
: is the photon energy, 
: are the rest energies of the proton and the antiproton, respectively, equals to m₀c², 
: are the kinetic energies of the proton and the antiproton, respectively, c: speed of light, and m₀: rest mass.</em>
Therefore the kinetic energy of the antiproton is:
<u>The proton mass is equal to the antiproton mass, so</u>:
Hence, the kinetic energy of the antiproton is 80.75 MeV.
I hope it helps you!
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