Answer:
0 degrees
Explanation:
Let 
are two forces. The resultant of two forces acting on the same point is given by :
Where 
is the angle between two forces
When 
i.e. when two forces are parallel to each other,
When 
i.e. when two forces are parallel to each other,
When 
i.e. when two forces are parallel to each other,
It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.
Explanation:
Given,
I = 5 A
V = 240 V
T = 25 mins = 1500 sec
Now,
Energy dissipated = IVT= 5×240×1500 = 1800000 J
Answer:
The heat flux between the surface of the pond and the surrounding air is<em> 60 W/</em>
<em> </em>
Explanation:
Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;
q = Q/A ...............................1
since we are working with the convectional heat transfer coefficient equation 1 become;
q = h (
) ........................2
where q is the heat flux;
Q is the heat energy that will be transferred;
h is the convectional heat coefficient = 20 W/.K;
is the surface temperature = 
C 23°C + 273.15 = 296.15 K;
is the surrounding temperature = 
C = 20°C + 273.15 = 293.15 K;
The values are substituted into equation 2;
q = 20 W/.K ( 296.15 K - 293.15 K)
q = 20 W/.K ( 3 K)
q = 60 W/
Therefore the heat flux between the surface of the pond and the surrounding air is 60 W/
Answer:
The surfer leave the surferboard with a velocity of 4.72[m/s]
Explanation:
This problem is related to the Conservation of Momentum, and it can be calculated using the following equation.
Where:
m1 = mass of the surfer = 42[kg]
v1 = velocity of the surfer before jumping = 5.2 [m/s]
m2 = mass of the surfboard = 22 [kg]
v2 = velocity of the surfboard before jumping = 5.2 [m/s]
Now after jumping
m1 = mass of the surfer = 42[kg]
v1' = velocity of the surfer after jumping = x
m2 = mass of the surfboard = 22 [kg]
v2' = velocity of the surfboard after jumping = 6.1 [m/s]
Now replacing in the equation.
![(42*5.2)+(22*5.2)= (42*X)+(22*6.1)\\42*X = 198.6\\x = 4.72[m/s]](https://tex.z-dn.net/?f=%2842%2A5.2%29%2B%2822%2A5.2%29%3D%20%2842%2AX%29%2B%2822%2A6.1%29%5C%5C42%2AX%20%3D%20198.6%5C%5Cx%20%3D%204.72%5Bm%2Fs%5D)
