Question

A 12 oz can of soda is left in a car on a hot day. In the morning the soda temperature was 60oF with a gauge pressure of 40 psi. What will the gauge pressure be when the soda reaches 90oF (or 363 Kelvin)?

Answer 1

Using the Gay Lussac's Pressure Temperature Law :
P1/T1 = P2/T2

Substituting the values: 
Let x be the new gauge pressure. 
40/60 = x/90
x = 60 psi.
The gauge pressure will be 60 psi when the soda reaches 90oF.