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ICE Princess25 [194]
3 years ago
14

Why should we convert units within the metric system?

Physics
1 answer:
dexar [7]3 years ago
6 0
We need it to calculate the how big it is, it’s mass, or even volume to get the measurements of lots of objects
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In the circuit shown in the figure above where R1 and R2 have equal resistance values, when switch S1 is closed, what voltage wo
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B. 3V as they both have the same resistance and the potential difference across the circuit could be divided by 2
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A soccer ball is kicked horizontally at 15.8 m/s off the top of a field house and lands 33.9 meters from the base of the field h
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First figure out the time by using the equation (you know v and x):
 v_{x} = \frac{x}{t} 

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y= v_{y} t+ \frac{1}{2}at^{2}

Remember that you can always analyze half of the scenario by dividing the time in half, and setting vy = 0 if at all it helps.

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4 years ago
A material used for electrical wiring must have _____.<br><br> B. high conductivity
dolphi86 [110]
If a material is going to be used for electrical wiring, it must have high conductivity. Electrical conductivity is the measure of a materials ability to allow the movement of an electric charge. Its SI is the Siemens per meter. Electrical conductivity is also known as specific conductance, a material with higher electrical conductivity would be the best preference for making electric wires. 
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4 years ago
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20 POINTS PLSSS!!!!!! I WILL MARK YOU AS BRAINLIEST!!!!
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A speed graph shows us how the speed of a moving object changes with time. The steeper the graph, the greater the acceleration. A horizontal line means the object is moving at a constant speed
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3 years ago
Compute the quantity of heat released by 25.0 g of steam initially at 100.0oC, when it is cooled to 34.0°C and by 25.0 g of wate
gayaneshka [121]

Answer:

For steam, heat released E = 15.26KJ

For water, heat released E2 = 6.91KJ

Explanation:

Given;

Mass(steam) ms = 25g

Mass (water) mw = 25g

Change in temperature of both steam and water ∆T = 100-34= 66°C

Specific heat of water C = 4.186 J/g.°C

Specific Latent heat L = 334J/g

For steam;

Heat released E = msL + msC∆T

E = (25×334) + (25×4.186×66)

E = 15256.9J

E = 15.26KJ

For water;

Heat released E2 = mwC∆T

E2 = 25×4.186×66

E2 = 6906.9J

E2 = 6.91KJ

5 0
3 years ago
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