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3 years ago

6

NEED HELP MULT CHOICE

2 answers:

Arturiano [62]3 years ago

6 0

Use a proportion.

Let the unknown height of the building be x.

x is to 39 m as 59 cm is to 71 cm.

x/39 = 59/71

71x = 39 * 59

x = 2301

x = 32.4

Answer: A. 32.4 m

olga nikolaevna [1]3 years ago

3 0

$\frac{h}{39} = \frac{59}{71}$ where h = height of the building

71h = 2,301

h = 32.4

A. 32.4 m

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Clara found the product of 3 – 6y2 and y2 + 2. Her work is shown below. (3 – 6y2)(y2 + 2) = 3(y2) + (–6y2)(2) = 3y2 – 12y2 = –9y

Lilit [14]

No he's not correct

<span>(3 – 6y2)(y2 + 2)
= 3(y2) -6(y2)(y2) - 6y2(2) </span>+ 3(2)<span>
= 3y2 -6y4 - 12y2 </span>+ 6 <span>
= -6y4 - 9y2 +6</span>

3 0

3 years ago

Please Help!!! Its math!

Veronika [31]

Answer:

$159

Step-by-step explanation:

All your doing is adding 45% and a percentage is out of 100 so to put it in decimal form it would be 0.45 added onto 159 which would give you $159.45 rounded to the nearest dollar would be $159

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3 years ago

Find the length of each side of the triangle determined by the three points P1,P2, and P3. State whether the triangle is an isos

Tanya [424]

Answer:

The triangle is both an Isosceles triangle and a right triangle.

Step-by-step explanation:

Given the vertices of a triangle.

$P_{1} = (- 1, 4)$

$P_{2} = (6, 2)$ and

$P_{3} = (4, - 5)$

We find the distance between all the points to determine the length of each side of the triangle.

Distance between any two points, say, $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\sqrt{\bigg ( \textbf{x}_{\textbf{2}} \hspace{1mm} \textbf{- x}_{\textbf{1}} \bigg )^{\textbf{2}} \textbf{+} \bigg( \textbf{y}_{\textbf{2}} \hspace{1mm} \textbf{- y}_{\textbf{1}} \bigg)^ {\textbf{2}}$

Length between $P_1$ and $P_{2}$ , (Side 1) :

$(x_1, y_1) = (- 1, 4)$ and

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{\bigg(6 - (-1) \bigg)^{2} \hspace{1mm} + \hspace{1mm} \bigg( 2 - 4 \bigg )^2$

$= \sqrt{7^2 + 2^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}}$

Length of Side 1 = $\sqrt{\textbf{53}}$ units.

Distance between $P_1$ and $P_2$ , (Side 2):

$(x_1, y_1) = (-1, 4)$

$(x_2, y_2) = (4, - 5)$

Distance = $\sqrt{ \bigg( 4 + 1 \bigg)^2 \hspace{1mm} + \bigg( - 5 - 4 \bigg ) ^2$

$= \sqrt{ 25 + 81 }$

$= \sqrt{\textbf{106}}$

Length of Side 2 = $\sqrt{\textbf{106}}$ units.

Distance between $P_2$ and $P_3$ , Side 3 :

$(x_1, y_1) = (4, 5)$

$(x_2, y_2) = (6, 2)$

Distance = $\sqrt{ 2^2 \hspace{1mm} + \hspace{1mm} 7^2}$

$= \sqrt{49 + 4}$

$= \sqrt{\textbf{53}$

Length of Side 3 = $\sqrt{\textbf{53}}$ units.

Note that the length of Side 1 = Length of Side 3.

That means the triangle is Isosceles.

Also, For a triangle to be right angle triangle, using Pythagoras theorem we have:

(Side 1)² + (Side 3)² = (Side 2)²

$\bigg( \sqrt{53} \bigg )^2 \hspace{1mm} + \hspace{1mm} \bigg( \sqrt{53} \bigg)^2 \hspace{1mm} = \hspace{1mm} \bigg ( \sqrt{106} \bigg ) ^2$

i.e, 53 + 53 = 106

Hence, the triangle is a right - angled triangle as well.

7 0

3 years ago

To solve -3 = -19 + d/5, what steps would you use?

Pachacha [2.7K]

To solve the expression, the steps are add 19 and multiply by 5

<h3>How to solve the expression</h3>

Given the equation;

-3 = -19 + d/5

First,

Collect like terms

-3+ 19 = d/5

Add the values on the left side

We have

16 = d/5

Cross multiply

16 × 5 = d

We then have

d = 80

Thus, to solve the expression, the steps are add 19 and multiply by 5

Learn more about algebraic expressions here:

brainly.com/question/4344214

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2 years ago

What is this property 14-8=2x+8-8<br> 6=2x

Molodets [167]

Answer:

Distributive?

Step-by-step explanation:

The way the problem is laid out confuses me but if it is the problem that you laid out, it should be Distributive.

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3 years ago