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salantis [7]
3 years ago
8

M+2-4=3 solve and get 50 pts

Physics
2 answers:
Colt1911 [192]3 years ago
6 0
Step^1: Problem: m + 2 - 4 =3 \\ Step^2: SolveThis: m - 5 = 0 ; 0 + 5 = 5 ; 5 -5 = 0 ; 5 + 0 = 5  \\ Answer: m = 5

good\\luck\\ on \\ your\\ assignment\\

                                  ~MeIsKaitlyn
Katen [24]3 years ago
3 0
Hey!

First, let's write the problem.
M+2-4=3
Subtract the numbers, we would do the following operation, 2-4=-2
M-2=3
Add 2 to both sides.
M-2+2=3+2

This tells us that our final answer would be,
M=5

Thanks!
-TetraFish
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What color of light must blue light mix with to create white light?
schepotkina [342]
<h2>Answer: a. Yellow </h2>

According to the additive theory of color, when we join the <u>three primary colors of light</u> (Red + Green + Blue) we get White light.

On the other hand we have <u>secondary colors of ligh</u>t that are:

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5 0
3 years ago
HELP PLSSSSSSSSSS<br> lithium has three protons. which model shows a neutral atom of lithium?
wolverine [178]

Answer:

B

Explanation:

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5 0
3 years ago
Read 2 more answers
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Sveta_85 [38]

Answer:

b.) Length

Explanation:

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8 0
3 years ago
250 mL 0.1 M HCl solution is mixed with 250 mL
pishuonlain [190]

Answer:

The concentration of OH⁻ in the mixture is 0.05 M

Explanation:

The reaction of neutralization between HCl and NaOH is the following:

H⁺(aq) + OH⁻(aq) ⇄  H₂O(l)

The number of moles of HCl is:

n_{HCl} = C*V = 0.1 mol/L*0.250L = 0.025 moles

Similarly, the number of moles of NaOH is:

n_{NaOH} = C*V = 0.2 mol/L*0.250L = 0.05 moles

Now, from the reaction of HCl and NaOH we have the following number of moles of NaOH remaining:

n_{NaOH} = 0.05 moles - 0.025 moles = 0.025 moles

Finally, the concentration of OH⁻ in the mixture is:

C =\frac{n_{NaOH}}{V_{T}}=\frac{0.025 moles}{0.250*2 L} = 0.05 moles/L

Therefore, the concentration of OH⁻ in the mixture is 0.05 M.

I hope it helps you!

8 0
3 years ago
I need help on 6 7,8 and 9
pantera1 [17]
6. F- DNA
7. C
8. G
9. D
I believe these are correct, hope this helps. 
7 0
3 years ago
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