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Svetlanka [38]
3 years ago
12

6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resi

stance? Why? ​
Physics
1 answer:
Nonamiya [84]3 years ago
5 0

\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
  • R is resistance

\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

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An ideal pendulum is often discussed when studying simple harmonic motion. What are the conditions needed for an ideal pendulum?
vlada-n [284]

Complete question is;

An ideal pendulum is often discussed when studying simple harmonic motion.

What are the conditions needed for an ideal pendulum? Check all that apply.

1) Gravitational force acts to pull the pendulum’s mass down.

2) The mass of the rod of the pendulum is evenly distributed along the rod.

3) The pivot on which the pendulum swings is frictionless.

4) The pendulum swings through its equilibrium position as a result of inertia.

5) Tension acts downward on the pendulum’s mass

Answer:

Conditions 2,3 & 4 are the ones that apply

Explanation:

The conditions required for an ideal pendulum are;

- The mass of the rod of the pendulum has to be evenly distributed along the rod.

- Ensure that the pivot on which the pendulum is swinging is frictionless

-The pendulum has to swing through it's equilibrium position as a result of inertia.

Thus,the correct options are 2, 3, 4.

6 0
3 years ago
Read 2 more answers
An object is placed near a concave mirror having a radius of curvature of magnitude 60 cm. How far should you place the object f
Viefleur [7K]

Answer:

u = 18 cm

Explanation:

given,

radius of curvature = 60 cm

magnification of mirror = 2.5

distance of object  = ?

R = 2 f

f = R/2

f = 60/2 = 30 cm

m = -\dfrac{v}{u}

2.5 = -\dfrac{v}{u}

v = -2.5 u

now,

Using mirror formula

\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}

\dfrac{1}{30} = \dfrac{1}{-2.5u} + \dfrac{1}{u}

\dfrac{1}{30} = \dfrac{0.6}{u}

u = 0.6 x 30

u = 18 cm

distance of object be equal to u = 18 cm

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How much time does it take for tweety’s bird cage to hit the ground after it was dropped if it reached a velocity of 22 meters p
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It matters on the weight

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A 9.0 cm object is 3.0 cm from a lens, which has a focal length of –12.0 cm.
artcher [175]
The answers are -2.4 for the distance. 7.2 for the height. Concave for the type
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3 years ago
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Plz help me answer this is my Final Exam!!!
Ostrovityanka [42]

It's answer number four

8 0
3 years ago
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