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Svetlanka [38]
3 years ago
12

6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resi

stance? Why? ​
Physics
1 answer:
Nonamiya [84]3 years ago
5 0

\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
  • R is resistance

\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

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Suppose that the inverse market demand for silicone replacement tips for Sony earbud headphones is p ​= pN ​- 0.1Q, where p is t
lbvjy [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   The effect of a change in the price of a new pair of headphones on the equilibrium price of replacement tips​ ( ​dp/dpN​) is

                   \frac{\delta p}{\delta p_N} =1

b

 The value of Q and p at equilibruim is

          Q_e = 250    and    p_d = 5

The consumer surplus is  C= 3125

The producer surplus  is   P = 375

Explanation:

      From the question we are told that

           The inverse market demand is  p_d = p_N -0.1Q

                The inverse supply function is     p_s = 2+ 0.012Q

a

The effect of change in the price  is mathematically given as

                  \frac{\delta p}{\delta p_N}

Now differntiating the inverse market demand function with respect to p_N

We get that  

                   \frac{\delta p}{\delta p_N} =1

b

   We are told that p_N =$30

        Therefore the inverse market demand becomes

                             p_d = 30 -0.1Q

At  equilibrium

                  p_d = p_s

So we have

               30 -0.1Q_e = 2+ 0.012Q_e

Where Q_e is the quantity at equilibrium

                    28 = 0.112Q_e

                     Q_e = \frac{28}{0.112}

                    Q_e = 250

Substituting the value of  Q into the equation for the inverse market demand function

                p_d = 30 - 0.1 (250 )

                    p_d = 5

Looking at the equation for p_d \ and \ p_s we see that

     For  Q =  0

             p_d = 30

             p_s =2

 And  for Q =  250

                 p_d = 5

                 p_s = 5

Hence the consumer surplus is mathematically evaluated as

           C = \frac{1}{2} * Q_e * (30 -5)

Substituting value

        C = \frac{1}{2} * 250 (30-5)

           C= 3125

And

  The  producer surplus is mathematically evaluated as

                    P = \frac{1}{2} *250 * (5-2)

                    P = 375

     

         

           

                     

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Answer:

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