The y-component of the stone's velocity when it is 8 m below the hand is 14.86 m / s
v² = u² + 2 a s
s = Displacement
u = Initial velocity
a = Acceleration
u = 8 m / s
s = 8 m
v² = 8² + 2 * 9.8 * 8
v² = 64 + 156.8
v = √ 220.8
v = 14.86 m / s
The equation used to solve the problem is an equation of motion. These equations are designed to locate an object in motion using components such as velocity, displacement, acceleration and time.
Therefore, the y-component of the stone's velocity is 14.86 m / s
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Answer:

Explanation:
We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between its mass and its acceleration:

where
F is the net force on the object
m is its mass
a is its acceleration
In this problem:
F = 40 N is the force on the object
m = 2 kg is its mass
Therefore, the acceleration of the object is

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