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VARVARA [1.3K]
3 years ago
8

Two asteroids are 50,000 m apart. one has a mass of 5 x 10^8 kg. If the force of gravity between them is 8.67 x 10 ^ -2 N, what

is the mass of the other asteroid?

Physics
2 answers:
Tema [17]3 years ago
6 0
6.5 *10^9 kg
is the mass of the second one

9966 [12]3 years ago
6 0

Answer:

The mass of the other asteroid is m_2=6.49\times 10^9\ kg.

Explanation:

Given that,

Mass of one asteroid, m=5\times 10^8\ kg

The separation between two asteroids, r = 50,000 m

The force of gravity between asteroids, F=8.67\times 10^{-2}\ N

We need to find the mass of the other asteroid. The gravitational force acting between two masses is given by :

F=G\dfrac{m_1m_2}{r^2}

m_2 is the mass of other asteroid

m_2=\dfrac{Fr^2}{Gm_1}

m_2=\dfrac{8.67\times 10^{-2}\times (50000)^2}{6.67\times 10^{-11}\times 5\times 10^8}

m_2=6.49\times 10^9\ kg

So, the mass of the other asteroid is m_2=6.49\times 10^9\ kg. Hence, this is the required solution.

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The y-component of the stone's velocity when it is 8 m below the hand is 14.86 m / s

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s = Displacement

u = Initial velocity

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The equation used to solve the problem is an equation of motion. These equations are designed to locate an object in motion using components such as velocity, displacement, acceleration and time.

Therefore, the y-component of the stone's velocity is 14.86 m / s

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