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VARVARA [1.3K]
3 years ago
8

Two asteroids are 50,000 m apart. one has a mass of 5 x 10^8 kg. If the force of gravity between them is 8.67 x 10 ^ -2 N, what

is the mass of the other asteroid?

Physics
2 answers:
Tema [17]3 years ago
6 0
6.5 *10^9 kg
is the mass of the second one

9966 [12]3 years ago
6 0

Answer:

The mass of the other asteroid is m_2=6.49\times 10^9\ kg.

Explanation:

Given that,

Mass of one asteroid, m=5\times 10^8\ kg

The separation between two asteroids, r = 50,000 m

The force of gravity between asteroids, F=8.67\times 10^{-2}\ N

We need to find the mass of the other asteroid. The gravitational force acting between two masses is given by :

F=G\dfrac{m_1m_2}{r^2}

m_2 is the mass of other asteroid

m_2=\dfrac{Fr^2}{Gm_1}

m_2=\dfrac{8.67\times 10^{-2}\times (50000)^2}{6.67\times 10^{-11}\times 5\times 10^8}

m_2=6.49\times 10^9\ kg

So, the mass of the other asteroid is m_2=6.49\times 10^9\ kg. Hence, this is the required solution.

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MatroZZZ [7]

Answer:

See the answers below.

Explanation:

to solve this problem we must make a free body diagram, with the forces acting on the metal rod.

i)

The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.

We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.

For the summation of forces we will take the forces upwards as positive and the negative forces downwards.

ΣF = 0

-15+T-W=0\\T-W=15

Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.

ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.

ΣM = 0

(15*9) - (18*W) = 0\\135 = 18*W\\W = 7.5 [N]

7 0
3 years ago
A light ray incident from medium 1 to medium 2, where n1>n2. When the incident angle exceed the critical angle ac, the refrac
vovikov84 [41]

Explanation:

(a)

Critical angle is the angle at the angle of refraction is 90°. After the critical angle, no refraction takes place.

Using Snell's law as:

n_1\times {sin\theta_i}={n_2}\times{sin\theta_r}

Where,  

{\theta_i}  is the angle of incidence

{\theta_r} is the angle of refraction = 90°

{n_2} is the refractive index of the refraction medium

{n_1} is the refractive index of the incidence medium

Thus,

n_1\times {sin\ \theta_{critical}}={n_2}\times{sin\ 90^0}

The formula for the calculation of critical angle is:

{sin\theta_{critical}}=\frac {n_2}{n_1}

Where,  

{\theta_{critical}} is the critical angle

(b)

No it cannot occur. It only occur when the light ray bends away from the normal which means that when it travels from denser to rarer medium.

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4 years ago
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Shkiper50 [21]

Answer:

10

Explanation:

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3 years ago
Dinitrogen oxide has?
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3 0
3 years ago
The horn on a fire truck sounds at a pitch of 350 hz a. what is the perceived frequency when the fire truck is moving toward you
solong [7]

The perceived frequency when the fire truck is moving toward you and away from you will be 370 Hz and 329.59 Hz respectively.

<h3>What is the Doppler effect?</h3>

A sudden change in the frequency due to the distance between the objects and source is explained by the doppler effect.

As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.

The perceived frequency when the fire truck is moving toward you;

\rm r' = (\frac{v+v_0}{v}) V \\\\ \rm r' = (\frac{343+20}{343}) 350 \\\\ r' =370.4  \  Hz

The perceived frequency when the fire truck is moving away from you;

\rm r' = (\frac{v-v_0}{v}) V \\\\ \rm r' = (\frac{343-20}{343}) 343 \\\\ r' =329.59  \  Hz

Hence, the perceived frequency when the fire truck in cases 1 and 2 will be 370 Hz and 329.59 Hz.

To learn more about the doppler effect refer to the link;

brainly.com/question/15318474

#SPJ1

5 0
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