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Elina [12.6K]
3 years ago
12

Give the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Giv

e the net ionic equation for the reaction (if any) that occurs when aqueous solutions of Al(C2H3O2)3 and LiNO3 are mixed. Al3+(aq) + 3 NO3-(aq) → Al(NO3)3(s) 3 Li+(aq) + (C2H3O2)33-(aq) → Li3(C2H3O2)3(s) Al3+(aq) + 3 NO3-(aq) + Li+(aq) + C2H3O2-(aq) → Al(NO3)3(aq) + LiC2H3O2(s) Li+(aq) + C2H3O2-(aq) → LiC2H3O2(s) No reaction occurs.
Chemistry
2 answers:
Sedaia [141]3 years ago
5 0
<h3><u>Answer;</u></h3>

No reaction occurs

<h3><u>Explanation;</u></h3>
  • An ionic equation is a chemical equation where the electrolytes in aqueous solution are written as dissociated ions.
  • These type of reactions are written only for reactions that occur in solution and are an attempt to show how the ions present are reacting.
  • In this case; when Al(C2H3O2)3 and LiNO3  are mixed, there will be no reaction that occurs, thus we can not write an ionic reaction since there is no chemical reaction took place between the two compounds.
Black_prince [1.1K]3 years ago
5 0

<u>Answer:</u> The correct answer is no reaction occurs.

<u>Explanation:</u>

We are given two aqueous solutions of Al(C_2H_3O_2)_3\text{ and }LiNO_3

The reaction between them follows:

Al(C_2H_3O_2)_3(aq.)+3LiNO_3(aq.)\rightarrow 3LiC_2H_3O_2(aq.)+Al(NO_3)_3(aq.)

Ionic equation for the above reaction follows:

Al^{3+}(aq.)+3(C_2H_3O_2)^-(aq.)+3Li^+(aq.)+3NO_3^-(aq.)\rightarrow 3Li^+(aq.)+3(C_2H_3O_2)^-(aq.)+Al^{3+}(aq.)+3NO_3^-(aq.)

As, all the ions gets dissolved in the water and no solid product is getting formed. Thus, no ionic equation can be written for the above reaction.

Hence, the correct answer is no reaction occurs.

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Answer:

Explanation:

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<em>no</em><em> </em>

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Determine how many grams of N2 are produced from the reaction of 8.37 g of H2O2 and 5.29 g of N2H4.
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mol = mass ÷ molar mass

If mass of hydrazine (N₂H₄)  = 5.29 g 
then mol of hydrazine           = 5.29 g ÷ ((14 ×2) + (1 × 4))
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mole ratio of hydrazine to Nitogen is     1   :  1
  ∴ if moles of hydrazine = 0.165 mol
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Mass = mol × molar mass

Since mol of nitrogen (N₂)  = 0.165
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5 0
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Answer:

The answer to your question is

1.-Fe₂O₃

2.- 280 g

3.- 330 g

Explanation:

Data

mass of CO = 224 g

mass of Fe₂O₃ = 400 g

mass of Fe = ?

mass of CO₂

Balanced chemical reaction

                       Fe₂O₃   + 3CO    ⇒  2Fe  +   3CO₂

1.- Calculate the molar mass of Fe₂O₃ and CO

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theoretical proportion Fe₂O₃ /3CO = 160/84 = 1.90

experimental proportion Fe₂O₃ / CO = 400/224 = 1.78

As the experimental proportion is lower than the theoretical, we conclude that the Fe₂O₃ is the limiting reactant.

3.-     160 g of Fe₂O₃  --------------- 2(56) g of Fe

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4.-      160 g of Fe₂O₃  --------------- 3(44) g of CO₂

          400 g of Fe₂O₃  --------------  x

          x = (400 x 132)/160

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