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3 years ago

Which of these indicate that a chemical reaction has occurred?

Chemistry

2 answers:

Pepsi [2]3 years ago

6 0

Your answer is C - Melting of a substance

tigry1 [53]3 years ago

3 0

I think b.) cause its evaporating

;)

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Can we used glass beaker instead of plastic cup for the calorimeter experiments?

Mice21 [21]

No, because plastic cups can be dissolved by organic compounds. Moreover, they are easily melted so a highly exothermic reaction can not be studied using them.

4 0

3 years ago

Man's scientific theories are often in correct because his knowledge is

Alik [6]

Answer:

Incomplete

Explanation:

I wouldn't say that a scientific theory is wrong.

It is the best we have at the time, based on all available knowledge .

As each new discovery is made, scientists modify the theory to fit the new knowledge.

The scientific method is a never-ending process.

8 0

2 years ago

Is a oak tree a invertebrates

viva [34]

Answer:

yes

Explanation:

oak trees don't have vertebrates

7 0

2 years ago

Read 2 more answers

A 5.00-L tank contains helium gas at 1.50 atm. What is the pressure of the gas in mmHg

bulgar [2K]

Answer:

1140 mmHg

Explanation:

1 atmosphere is 760 mmHg, so 1.5 atmospheres is ...

1.5×760 mmHg = 1140 mmHg

4 0

3 years ago

Given the following equilibrium constants: Kb B(aq) + H2O(l) ⇌ HB+(aq) + OH−(aq) 1/Kw H+(aq) + OH−(aq) ⇌ H2O(l) What is the equi

bija089 [108]

Answer: The value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

Explanation:

The given chemical equations follows:

Equation 1: $B(aq.)+H_2O(l)\rightleftharpoons HB^+(aq.)+OH^-(aq.);K_b$

Equation 2: $H^+(aq.)+OH^-(aq.)\rightleftharpoons H_2O(l);\frac{1}{K_w}$

The net equation follows:

$B(aq.)+H^+(aq.)\rightleftharpoons HB^+(aq.);K_c$

As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K_c=K_1\times K_2$

We are given:

$K_1=K_b$

$K_2=\frac{1}{K_w}$

Putting values in above equation, we get:

$K_c=K_b\times \frac{1}{K_w}=\frac{K_b}{K_w}$

Hence, the value of $K_c$ for the net reaction is $\frac{K_b}{K_w}$

7 0

2 years ago