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gogolik [260]
3 years ago
15

Which of these indicate that a chemical reaction has occurred?

Chemistry
2 answers:
Pepsi [2]3 years ago
6 0
Your answer is C - Melting of a substance 
tigry1 [53]3 years ago
3 0

I think b.)  cause its evaporating


;)

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What is the answer to 2.5 * 22.5
nadya68 [22]
Your answer to 2.5*22.56 is 56.25
4 0
3 years ago
The Valence Electrons of an Atom of Which Element would feel a Greater Effective Nuclear Charge than the Valence?
kumpel [21]
The effective nuclear charge is an innate property of a specific element. It is the pull of force that an electron feels from the nucleus. It is related to the valence electron by the equation: Z* = Z-S, where Z* is the effective nuclear charge, Z is the atomic number and S is the shielding constant.

For the following elements in the choices, these are their values of Z*:

Aluminum - +12.591
Beryllium - +1.912
Hydrogen - +1
Carbon - +4

The effective nuclear charge of Boron is +3. Thus, the answers are  Aluminum and Carbon.
5 0
3 years ago
What volume of 0.100 M HCl will react completely with 50.00 mL of 0.200 M NaOH?
skelet666 [1.2K]
Equation of reaction
Hcl+NaoH-->Nacl+H2O
1:1
Using the formula CaVa/CbVb=na/nb
Ca(Concentation of acid)= 0.100M
Cb(Concentration of base)=0.200M
Va=?
VB=50.00ml
na=1
nb=1
from the formula
Va= CbVbna/Canb
Va= 0.2*50*1/0.1*1
=10/0.1=100ml
Therefore volume of acid = 100ml
7 0
3 years ago
What is the ph value of the produced solution when hcl reacts with naoh ?
algol13

Answer:

The answer to your question is: 7

Explanation:

The reaction between HCl and NaOH is a neutralization reaction, that means that the products will be water and a salt and the pH will be 7.

                     HCl + NaOH  ⇒  NaCl + H₂O

4 0
3 years ago
A 100.0 mL sample of 0.300 M NaOH is mixed with a 100.0 mL sample of 0.300 M HNO3 in a coffee cup calorimeter. If both solutions
Mars2501 [29]

Answer:

Qm  = -55.8Kj/mole

Explanation:

NaOH(aq) + HNO₃(aq) => NaNO₃(aq) + H₂O(l)

Qm = (mc∆T)water /moles acid

Given => 100ml(0.300M) NaOH(aq) + 100ml(0.300M)HNO₃(aq)

=> 0.03mole NaOH(aq) + 0.03mole HNO₃(aq)

=> 0.03mole NaNO₃(aq) + 0.03mole H₂O(l)

ΔH⁰rxn = [(200ml)(1.00cal/g∙°C)(37 – 35)°C]water / 0.03mole HNO₃

= 13,333 cal/mole x 4.184J/cal = 55,787J/mol = 55.8Kj/mole (exothermic)*

Heat of reactions comes from formation of H-Oxy bonds on formation of water of reaction and heats the 200ml of solvent water from 35⁰C to 37⁰C.

4 0
3 years ago
Read 2 more answers
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