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3 years ago

6

Whats the answer to 7/2 × 1/5?

2 answers:

charle [14.2K]3 years ago

5 0

Answer:7/10

Explanation:multiply top and bottom

svp [43]3 years ago

3 0

The answer to the problem is 7/10

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What is the total volume of solution that was dispensed from this burette? before <br><br> after

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Describe the pattern that thermal energy follows as it moves

mars1129 [50]

When you bring two objects of different temperature together, energy will always be transferred from the hotter to the cooler object. The objects will exchange thermal energy, until thermal equilibrium<span> is reached, i.e. until their temperatures are equal. We say that </span>heat<span>flows from the hotter to the cooler object. </span><span>Heat is energy on the move.</span> <span>
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3 years ago

What's the volume of one mole of an ideal gas at Standard Temperature and Pressure? Question 17 options: A) 11.2 L B) 22.4 L C)

mel-nik [20]

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3 years ago

The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur

Sveta_85 [38]

Answer: Heat of vaporization is 41094 Joules

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

$ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})$

where,

$P_1$ = initial pressure at 429 K = 760 torr

$P_2$ = final pressure at 415 K = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 429 K

$T_2$ = final temperature = 515 K

Now put all the given values in this formula, we get

$\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]$

$\Delta H=41094J$

Thus the heat of vaporization is 41094 Joules

4 0

3 years ago

If 842 grams of sodium hydroxide reacts with 750.0 grams of aluminum, how many grams of aluminum hydroxide should theoretically

Phantasy [73]

548.55 grams of aluminum hydroxide should theoretically form.

Explanation:

Balanced equation for the reaction:

3 NaOH + Al ⇒ Al(OH)3 +3 Na

DATA GIVEN:

mass of NaOH = 842 grams, atomic mass =39.9 grams/mole

mass of Al = 750 grams, atomic mass = 26.9 grams/mole

aluminum hydroxide theoretical yield = ?

Moles of NaOH reacted

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation

NaOH = $\frac{842}{39.9}$

= 21.1 MOLES OF NaOH

Al = $\frac{750}{26.9}$

= 27.8 moles

from the equation

from 3 moles of NaOH 1 mole of Al(OH)3 is produced

21.1 moles of NaOH will react to give x moles of Al(OH)3

$\frac{1}{3}$ = $\frac{x}{21.1}$

7.03 moles of Al(OH)3 is formed.

and

1 mole of Al(OH)3 is formed from 1 mole of Al in the reaction

so, 27.8 Moles will react to give give 27.8 moles of Al(OH)3 limiting reagent of the given reaction is NaOH

mass of Al(OH)3 =7.03 x 78 (atomic mass of Al(OH)3)

= 548.55 grams

theoretical yield from the given data is 548.55 grams

3 0

3 years ago