The force on a charged particle in a magnetic field is given by
the speed of the charged particle = 10842 m/s.
Explanation:
F= q V B sinθ
F=force=3.5 x 10⁻²N
q= charge= 8.4 x 10⁻⁴ C
B= magnetic field= 6.7 x 10⁻³ T
θ=35⁰
Thus the velocity is given by V=
V=(3.5 x 10⁻²)/[(8.4 x 10⁻⁴)(6.7 x 10⁻³)(sin35)]
V=10842 m/s
Answer:
the angle, in radians, between the central maximum = 2.87degree or 0.05radians
Explanation:
The detailed steps and appropriate formula is as shown in the attachment.
Using λm = dsin teta
where d =20λ, m = 1
from the formula, sin teta = λ/20λ
= sin teta = 0.05
teta = arc sin(0.05) = 2.87 degree
