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3 years ago

How many grams are there in 9.40*10^25 molecules of H2

1 answer:

5 0

>4Dt. 1950 y fueron. 45Dys Imox x Na motu cues G.91 %10° mole cultes. 3) How many grams are there in 2.3 x 1024 atoms of silver? 2, 3x 10°tatoms x Imol.<

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In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance. What is the total resistance?

Sauron [17]

Answer:

17 ohms

Explanation:

Given that,

In a series circuit there are 17 light bulbs, each providing 1 ohm of resistance.

We need to find the total resistance of the circuit.

The equivalent resistance for series combination is given by :

$R_{eq}=R_1+R_2+....$

For 17 light bulbs, the equivalent resistance is given by :

$R_{eq}=R+R+....\text{upto 17 terms}\\\\R_{eq}=17R\\\\=17$

Hence, the total resistance is 17 ohms. Hence, the correct option is (d).

7 0

3 years ago

The substances present before a chemical reaction takes place are called?

andrew11 [14]

The substances present before the reaction are the reactants. (As the reaction goes through, the substances that are produced are called the products of the reaction).

5 0

3 years ago

Read 2 more answers

When an atom is in the ground state what must happen for the atom to be in an excited state? what must happen for this atom to r

scoray [572]

Hi there

In order for an electron to jump into a higher energy state, it must first absorb energy (heat, light, etc).

When an electron goes back down to the ground state from the excited state, it emits energy usually in the form of a photon.

i hope this helps

4 0

3 years ago

In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?

sveta [45]

Answer:

Explanation:

The number of the them will result in A.

7 0

2 years ago

In Lab 10 you make a stock solution of salicylic acid, and then four dilutions. The stock solution is made by diluting 5.00 ml o

Zigmanuir [339]

Answer:

Stock solution = 1.25 *10^-3 M

Dilution 1 = 5*10^-4 M

Dilution 2= 3.75 * 10^-4 M

Dilution 3 = 2.5 *10^-4 M

Dilution 4 = 1.25 *10^-4 M

Explanation:

Step 1: Data given

The stock solution is made by diluting 5.00 ml of 1.250 x 10-2 M salicylic acid in 50.00 mL of solution.

Step 2: Calculate the concentration of the stock solution:

M1*V1 = M2*V2

⇒ with M1 = the initial concentration = 1.250 *10^-2 M

⇒ with V1 = 5 mL = 5*10^-3 L

⇒ with M2 = TO BE DETERMINED

⇒ with V2 = 50 mL = 50 *10^-3 L

M2 = (M1*V1)/V2

M2 = (1.250 *10^-2 * 5*10^-3 L) / 50 *10^-3

M2 = 0.00125 M = 1.25 *10^-3 M

Step 3: Calculate dilution 1

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 *10^-3)/(25*10^-3L)

M2 = 0.0005 M = 5*10^-4 M

Step 4: Calculate dilution 2

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 10 * 7.5*10^-3)/(25*10^-3)

M2 = 0.000375 M = 3.75 * 10^-4 M

Step 5: Calculate dilution 3

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 5*10^-3) /(25*10^-3)

M2 = 0.00025 M = 2.5 *10^-4 M

Step 6: Calculate dilution 4

M2 = (M1*V1)/V2

M2 = (1.25*10^-3 * 2.5*10^-3)/(25*10^-3)

M2 = 0.000125 M = 1.25 *10^-4 M

5 0

3 years ago