All categories

3 years ago

The characteristic bright-line spectrum of an atom is produced when

1 answer:

8 0

Bright Line Emission Spectrum: As the excited electron returns to ground state (it's lower energy level) the energy it originally absorbed is released as discrete lines of light.

You might be interested in

Explain the relationship between chemical bonds and energy in the body.

uysha [10]

It is a very simple explanation. When the chemical bonds are broken inside our body, the energy that gets released in our body is used to perform several important functions. This is the main relation between chemical bonds and energy in the body. I hope that this is the answer that has come to your great help.

6 0

3 years ago

During fusion

Veronika [31]

Answer:

Explanation:

uranium atoms are fused together

3 0

3 years ago

Read 2 more answers

What element is found in large amounts in muscle tissue and nerve tissue?

ra1l [238]

Calcium maybe... Because it has protein lol

7 0

3 years ago

When sugar is mixed with water, equilibrium is reached when __________?

pashok25 [27]

<span>Sugar is mixed with wateer, equilibrium is reached in the dissolved sugar molecules are evenly distributed throughout the solution.</span>

8 0

3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

<em>B) Radius</em>

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

3 0

3 years ago