Answer:
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓
Ksp = [2s]² . [s] → 4s³
Explanation:
Ag₂CrO₄ → 2Ag⁺ + CrO₄⁻²
Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.
2Ag⁺ (aq) + CrO₄⁻² (aq) ⇄ Ag₂CrO₄ (s) ↓ Ksp
That's the expression for the precipitation equilibrium.
To determine the solubility product expression, we work with the Ksp
Ag₂CrO₄ (s) ⇄ 2Ag⁺ (aq) + CrO₄⁻² (aq) Ksp
2 s s
Look the stoichiometry is 1:2, between the salt and the silver.
Ksp = [2s]² . [s] → 4s³
Answer:
9 g/ml
Explanation:
5 + 3.3 = 8.5
But you should use sig figs.
5 has no tenths, hundredths, and etc.
Therefore the 8.5 rounds up to 9
So the answer is 9.
Answer:
2
Explanation:
Each orbital can hold two electrons. One spin-up and one spin-down.
(4) Zirconium
This element is often used in the chemical production field, and as implants due to its high chemical resistance and stability.
