Answer:
COMPLETE QUESTION:
To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark
e)To the 11th mark
ANSWER : Option D (To the 7 1/3 mark)
Step-by-step explanation:
First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e
Volume of cylinders
π x R² x 4 = πxr²x 6
R²/r² = 6/4
after both cylinder were emptied
π x R² x h = π x r² x 11
R²/r² = 6/4 = 11/h
h = (4 x 11) /6 = 22/3 = 7 1/3 mark
Therefore, the height of the water in the wide cylinder is 7 1/3
The answer is 2.67 seconds per second when rounded but 2.66666...
Th z-score is given by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
hence:
z=(240-200)/20
z=2
Answer:
This problem is about linear equations. We assume Dale drive X miles, and the total cost is $Y, then we can get:
Plan I: Y=38+0.11X
Plan II: Y=49+0.07X
When both plans cost the same, 38+0.11X=49+0.07X. We will get X = 275miles, and Y=$68.25
Step-by-step explanation:
Answer:
Soup B
Step-by-step explanation:
Given :
Soup A:
Sodium(mg) 720
Ounces 6 1
Soup B :
Sodium(mg) 600
Ounces 4 1
To Obtian the amount of sodium per ounce in each of soup A and B
Soup A :
Sodium per ounce = 720 mg / 61 = 11.803 mg / ounce
Soup B:
Sodium per ounce = 600 mg / 41 = 14.634mg / ounce
Hence. SOUP B contains more soudiun per ounce
