The equivalent of the Newton's second law for rotational motions is:
where
is the net torque acting on the object
is its moment of inertia
is the angular acceleration of the object.
Re-arranging the formula, we get
and since we know the net torque acting on the (vase+potter's wheel) system,
, and its angular acceleration,
, we can calculate the moment of inertia of the system:
Answer:
a) 15.77 m/sec2
b) 13.3 deg
Explanation:
we are given;
Flea force = F1=1.07×10⁻5 N j
Breeze force = F2 = 1.14× 10⁻6 N (-j
mass of flea =6.0 ×10⁻7 kg
So net force on the flea=F1+F2+weight of flea=1.07×10⁻5 j +1.14× 10⁻6 i + 6.0 ×10⁻7 (-j) ×9.8= ma
==> ma = 1.07×10⁻5 j - 0.588×10⁻5 j + 0.114×10⁻5 i
==> ma= 0.482 ×10⁻5 j +0.114×10⁻5 i
==> ma = 0.114×10⁻5 i +0.482 ×10⁻5 j
== a = (0.114×10⁻5 i +0.482 ×10⁻5 j) / 6.0 ×10⁻7
==> a =
==>a= (1.9 j+8.03 i ) m/sec2
mag of a 
= 15.77 m/sec2
direction angle = tan⁻1(1.9/8.03)=13.3°
B the desert was once covered in water
Answer:
13 m/s east
Explanation:
We can solve the problem by using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision:
where
m = 0.1 kg is the mass of each puck
u1 = +13 m/s is the initial velocity of puck 1
u2 = -18 m/s is the initial velocity of puck 2 (here I assume the west direction to be the negative direction, so I put a negative sign)
v1 = -18 m/s is the final velocity of puck 1
v2 = ? is the final velocity of puck 2
Simplifying m from the formula and substituting the data, we can find the final velocity of puck 2, v2:
And the positive sign means that puck 2 is moving east.
Answer:
4.86 seconds
Explanation:
Velocity of projection, u = 14 m/s
angle of projection, θ = 20°
Formula for the time of flight
For earth
Te = (2 x 14 x Sin 20) / 9.8
Te = 0.98 s
For moon
g' = g/6 = 1.64 m/s^2
Tm = ( 2 x 14 x Sin 20) / 1.64
Tm = 5.84 seconds
Tm - Te = 5.84 - 0.98 = 4.86 s
So, it takes 4.86 s more time of flight on moon than the earth.
