These are the correct answers. I couldn't get the rest of the answers
Answer:
44 ohm, 145 ohm
Explanation:
R = 44 ohm, L = 2.2 mH = 2.2 x 10^-3 H
At f = 60 Hz
XL = 2 π f L = 2 x 3.14 x 60 x 2.2 x 10^-3 = 0.82896 ohm
Impedance,
Z = 44 ohm
At f = 10 kHz = 10000 Hz
XL = 2 π f L = 2 x 3.14 x 10000 x 2.2 x 10^-3 = 138.16 ohm
Impedance,
Z =1 45 ohm
Answer:
Acceleration,
Explanation:
Given that,
Mass of the planet Krypton,
Radius of the planet Krypton,
Value of gravitational constant,
To find,
The acceleration of an object in free fall near the surface of Krypton.
Solution,
The relation for the acceleration of the object is given by the below formula as :
So, the value of acceleration of an object in free fall near the surface of Krypton is
To solve this problem it is necessary to apply the concepts related to pressure as a unit that measures the force applied in a specific area as well as pressure as a measurement of the density of the liquid to which it is subjected, its depth and the respective gravity.
The two definitions of pressure can be enclosed under the following equations
Where
F= Force
A = Area
Where,
Density
g = Gravity
h = Height
Our values are given as,
If we make a comparison between the lid and the tube, the diameter of the tube becomes negligible.
Matching the two previous expressions we have to
Re-arrange to find h
Therefore the height of water in the tube is 7.9cm
Answer:
4 cm/s².
Explanation:
From the question given above, the following data were obtained from it:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
Acceleration is simply defined as the rate of change of velocity with time. Mathematically, it is expressed as follow:
Acceleration (a) = Change in velocity /time
Acceleration (a) = [final velocity (v) – initial velocity (u)] /time (t)
a = (v – u) /t
With the above formula, we can obtain the acceleration of the ball as follow:
Initial velocity (u) = 0 cm/s
Final velocity (v) = 40 cm/s
Time (t) = 10 s
Acceleration (a) =?
a = (v – u) /t
a = (40 – 0) / 10
a = 40/10
a = 4 cm/s²
Therefore, the acceleration of the ball is 4 cm/s²