1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gre4nikov [31]
2 years ago
11

Helppp pls yes or no question

Physics
2 answers:
svp [43]2 years ago
7 0

Answer:

yes, should be

Explanation:

This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.

Nana76 [90]2 years ago
7 0

Answer:

They appear to be about the same height, so the answer is true.

Explanation:

You might be interested in
Each driver has mass 79.0 kg. Including the masses of the drivers, the total masses of the vehicles are 800 kg for the car and 4
Mademuasel [1]

Answer:

Force exerted on the car driver by the seatbelt = 8139.4 N = 8.14 kN

Force exerted on the truck driver by the seatbelt = 1628.2 N = 1.63 kN

It is evident that the driver of the smaller vehicle has it worse. The car driver is in way more danger in this perfectly inelastic head-on collision with a bigger vehicle (the truck).

Explanation:

First of, we calculate the velocity of the vehicles after collision using the law of conservation of Momentum

Momentum before collision = Momentum after collision

Since the collision of the two vehicles was described as a head-on collision, for the sake of consistent convention, we will take the direction of the velocity of the bigger vehicle (the truck) as the positive direction and the direction of the car's velocity automatically is the negative direction.

Velocity of the truck before collision = 6.80 m/s

Velocity of the car before collision = -6.80 m/s

Let the velocity of the inelastic unit of vehicles after collision be v

Momentum before collision = (4000)(6.80) + (800)(-6.80) = 27200 - 5440 = 21,760 kgm/s

Momentum after collision = (4000 + 800)(v) = (4800v) kgm/s

Momentum before collision = Momentum after collision

21760 = 4800v

v = (21760/4800)

v = 4.533 m/s (in the direction of the big vehicle (the truck)

So, we then apply Newton's second law of motion which explains that the magnitude change in momentum is equal to the magnitude of impulse.

|Impulse| = |Change in momentum|

But Impulse = (Force exerted on each driver by the seatbelt) × (collision time) = (F×t)

Change in momentum = (Momentum after collision) - (Momentum before collision)

So, for the driver of the truck

Initial velocity = 6.80 m/s (the driver moves with the velocity of the truck)

Final velocity = 4.533 m/s

Change in momentum of the truck driver = (79)(6.80) - (79)(4.533) = 179.1 kgm/s

(F×t) = 179.1

F × 0.110 = 179.1

F = (179.1/0.11)

F = 1628.2 N = 1.63 kN

So, for the driver of the car

Initial velocity = -6.80 m/s (the driver moves with the velocity of the car)

Final velocity = 4.533 m/s

Change in momentum of the car driver = (79)(-6.80) - (79)(4.533) = -895.3 kgm/s

(F×t) = |-895.3|

F × 0.110 = 895.3

F = (895.3/0.11)

F = 8139.4 N = 8.14 kN

Hope this Helps!!!

3 0
3 years ago
An object weighs 39.36 newtons. What is its mass if a gravitometer indicates that g = 9.83 m/s2?
CaHeK987 [17]
The force applied to an object is said to be a product of its mass and the acceleration. For this case, acceleration is the reading on the gravitometer. We calculate as follows:

F = mg
39.36 N = m(9.83 m/s^2)
m = 4.00 kg

Hope this answers the question. Have a nice day.
6 0
3 years ago
Read 2 more answers
A wave has a length of 8 meters and a speed of 32 meters per second. What is the frequency of the wave
Naddika [18.5K]

Answer:

The frequency of wave is 4 hertz.

Explanation:

Given,

wave length = 8m

speed of sound ( v) = 32 m/s

frequency ( f) = ?

we know,

v = f × lambda

or, 32 = f × 8

or, f = 32/8

or, f = 4 Hertz.

5 0
3 years ago
Which of the following is NOT an exercise myth?
Blababa [14]
It is <span>C. Low to moderate level of exertion can be sustained over long periods of time </span>
7 0
2 years ago
A car is traveling on a level road at a constant rate of speed. What additional force is necessary to bring the car into equilib
iragen [17]

Answer: Zero.

Explanation:

By the first Newton's law, we know that:

every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force.

Now, we know that the car is moving with constant speed, then there is no net force acting on the car, which means that the car is already in equilibrium.

Then if we add one force to the situation, the car will not be anymore in equilibrium.

The correct option is zero.

5 0
3 years ago
Other questions:
  • Janel did an experiment to see which spices can kill bacteria. She mixed a spice with bacteria food called agar. She poured the
    7·1 answer
  • A car traveled at a constant velocity of 70 mph from noon to 2:00 pm. At 3:00 pm the velocity of the car was 80 mph; and finally
    8·1 answer
  • Which of the following is a likely outcome of a failed experiment?
    12·1 answer
  • 2. Jessie studies seaweed and she usually takes large amounts of samples. She would take
    7·1 answer
  • Explain Newton’s 3 laws of motion by using the example of a rollercoaster?
    9·1 answer
  • How many atoms of hydrogen are in vitamin B
    8·1 answer
  • Why are stars considered to be the building blocks of the universe?
    8·2 answers
  • PLEASE HELP ASAPPPPPPPPP
    13·1 answer
  • What is an effect of La Nina?
    6·1 answer
  • What is the spring constant if 85.0J of energy is stored when a spring is compressed 0.400m?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!