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cestrela7 [59]
3 years ago
14

The vertical component of the magnetic induction in the Earth's magnetic field at Hobart is approximately 6×10-5T upward. What e

lectric field is set up in a car travelling on a level surface at 100 km h-1due to this magnetic field? Which side or end of the car is positively charged? Approximately what p.d. is created across a car of typical size?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

Explanation:

Magnetic field B = 6 X 10⁻⁵ T.

Width of car = L (Let )

Velocity of car v  = 100 km/h

= 27.78 m /s

induced emf across the body ( width )  of the car

= BLv

= 6 X 10⁻⁵ L X 27.78

166.68 X 10⁻⁵ L

Induced electric field across the width

= emf induced / L

E =  166.68 X 10⁻⁵ N/C

We suppose breadth of a typical car = 1.5 m

potential difference induced

= 166.68 x 1.5 x 10⁻⁵

250 x 10⁻⁵ V

= 2.5 milli volt.

The side of the car which is positively charged depends on the direction in which car is moving , whether it is moving towards the north or south.

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Answer:

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Explanation:

Given that:

A type of cuckoo clock keeps time by having a mass bouncing on a spring, usually something cute like a cherub in a chair.

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where;

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By making k the subject of the formula; we have:

\mathtt{T^2 = 4 \pi^2 (\dfrac{m}{k})}

\mathtt{k =\dfrac{4 \pi ^2 \ m}{T^2}}

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\mathtt{k =\dfrac{39.49 \ \times 0.0150 }{0.25}}

\mathtt{k =\dfrac{0.59235 }{0.25}}

k = 2.369 N/m

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At the start of a basketball game, a referee tosses a basketball straight into the air by giving it some initial speed. After be
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Answer:

0.32 m.

Explanation:

To solve this problem, we must recognise that:

1. At the maximum height, the velocity of the ball is zero.

2. When the velocity of the ball is 2.5 m/s above the ground, it is assumed that the potential energy and kinetic energy of the ball are the same.

With the above information in mind, we shall determine the height of the ball when it has a speed of 2.5 m/s. This can be obtained as follow:

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Thus,

PE = KE

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