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Murrr4er [49]
3 years ago
15

The sum of 5 consecutive integers is 205. What is the third number?

Mathematics
1 answer:
Elza [17]3 years ago
7 0
If 5 consecutive integers is 205,

then a + b + c + d + e = 205
 but also, each integer is separated  by a difference of 1

⇒  a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒  5a + 10 = 205
⇒            5a = 195
⇒               a = 39

∴ third term = 39 + 2
                     = 41
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Solve by using Pythagorean Theorem, a= 5, b= x-1, and c=x
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Step-by-step explanation:

The given is,

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             b = x - 1

             c = x

Step:1

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      (  It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides )

      From the given values the equation (1) becomes,

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               25 + ( x^{2} + 1 - 2x ) = x^{2}

                           25 + 1 -2x = 0               ( ∵ Eliminate x^{2} in both sides)

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Result:

            The value of x is 13, from the values of x the values of a,b and c becomes 5, 12 and 13, which is obtained by using Pythagorean theorem.

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