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2 years ago

The sum of 5 consecutive integers is 205. What is the third number?

1 answer:

7 0

If 5 consecutive integers is 205,

then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1

⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39

∴ third term = 39 + 2
= 41

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$k:\ 9x+7y=6\ \ \ |-9x\\\\7y=-9x+6\ \ \ \ |:7\\\\y=-\dfrac{9}{7}x+\dfrac{6}{9}\to m_1=-\dfrac{9}{7}\\\\l:\ y=m_2x+b\\\\l\ \perp\ k\iff-\dfrac{9}{7}m_2=-1\ \ \ \ |\cdot\left(-\dfrac{7}{9}\right)\\\\m_2=\dfrac{7}{9}\to\ l:\ y=\dfrac{7}{9}x+b$

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3 years ago

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Given the weekly deductions raised, the annual Federal Tax deduction is $ 3,189.68.

Given that the deductions for the week were: Federal Tax $ 61.34, FICA $ 52.05, and State $ 7.92; To determine what is the annual Federal Tax deduction, the following calculation must be performed:

The weekly deduction must be multiplied by the number of weeks that a year has, to obtain the final amount of taxes.

$ 61.34 x 52 = X
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Therefore, the annual Federal Tax deduction is $ 3,189.68.

Learn more in brainly.com/question/25225323

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