Answer:
False
Explanation:
On the left side of the equation (Li + O2), there is 1 Li atom and 2 O atoms.
but on thw right side of the equation (Li2O,) there is 2 Li atoms and 1 O atom
1 mole of an alkane gives 2 moles is correct answer
Answer:
15.4 g of sucrose
Explanation:
Formula to be applied for solving these question: colligative property of freezing point depression. → ΔT = Kf . m
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Let's replace data given: 0°C - (-0.56°C) = 1.86 C/m . m
0.56°C / 1.86 m/°C = m → 0.301 mol/kg
m → molality (moles of solute in 1kg of solvent)
Our mass of solvent is not 1kg, it is 150 g. Let's convert it from g to kg, to determine the moles of solute: 150 g. 1kg/1000g = 0.150 kg
0.301 mol/kg . 0.150kg = 0.045 moles.
We determine the mass of sucrose, by the molar mass:
0.045 mol . 342 g/1mol = 15.4 g
Well a question to ask would be if the mass of the material has changed significantly as that would determine that the substance is radioactive or if there have been any high readings found by a Geiger meter in certain period of time
hope that helps
The compound NaH2PO4 name is
sodium dihydrogen phosphate
Explanation
This name is arrived at by using the IUPAC rules of naming compound
1. the metal (sodium)is named first followed by the ligand ( hydrogen and phosphate)
Ligand are molecules that are attached to the metal center.
2. ligand are named using alphabetical order(for our case h for hydrogen come before p for phosphate hence hydrogen is named first)
3. Prefix di is used since hydrogen are two
hence the name of the compound is Sodium dihydrogen phosphate
