All categories

3 years ago

An inward force that tends to minimize the surface area of a liquid

Chemistry

2 answers:

dusya [7]3 years ago

4 0

Surface tension , hope this helped ! :)

bulgar [2K]3 years ago

3 0

Surface tensionnnnnnnnn

You might be interested in

Why would you need a locating agent in an experiment to separate amino acids by chromatography

Nadusha1986 [10]

A locating agent is needed in an experiment to separate amino acids by chromatography as it helps to analyze colorless substances on paper.

<h3>What is chromatography?</h3>

Chromatography is an analytical method frequently used to separate a chemical mixture into its components, allowing for in-depth analysis of each component.

There are many different types of chromatography including liquid, gas, ion-exchange, and affinity chromatography, but they all use the same basic principle.

<h3>What is the use of a locating agent in Chromatography?</h3>

In paper chromatography, colorless compounds are examined using a locating agent.

It is a chemical that combines with colorless substances to produce colorful compounds that are easy to see for analysis. Ninhydrin spray is an example of a locating agent of this type.

Thus, a locating agent is used in an experiment to separate amino acids by chromatography as it helps in determining colorless substances on paper.

Learn more about chromatography:

brainly.com/question/11960023

#SPJ9

5 0

1 year ago

10. Which of the following best describes the reaction 2VO3– (aq) + Zn (s) + 8H+ (aq) → 2VO2 (aq) + Zn2+ (aq) + 4H2O (l)? ______

Oduvanchick [21]

Correct answer is option E. <span>It is a redox reaction in which Zn is oxidized at the anode, and V is reduced at the cathode.

Reason:
In above reaction, the oxidation state of VO3- is +5, while that of VO2 is +4. Thus there is reduction of V from +5 to +4
In case of Zn, oxidation state of Zn is increased from 0 to +2, Thus process is referred as oxidation. </span>

3 0

2 years ago

For many purposes we can treat ammonia NH3 as an ideal gas at temperatures above its boiling point of −33.°C. Suppose the temper

Keith_Richards [23]

Answer:

The new pressure will be 0.225 kPa.

Explanation:

Applying combined gas law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1\text{ and }V_1$ are initial pressure and volume at initial temperature $T_1$ .

$P_2\text{ and }V_2$ are final pressure and volume at initial temperature $T_2$ .

We are given:

$P_1=0.29 kPa\\V_1=V\\P_2=?\\V_2=V+50\% of V=1.5 V$

$T_1=-25^oC=248.15 K$

$T _2 = 16^oC=289.15 K$

Putting values in above equation, we get:

$\frac{0.29 kPa\times V}{248.15 K}=\frac{P_2\times 1.5V}{289.15 K}$

$P_1=0.225 kPa$

Hence, the new pressure will be 0.225 kPa.

4 0

3 years ago

Which of the following are the bark, roots, seeds, buds or berries of an aromatic plant?

djverab [1.8K]

Answer:

Spices

Explanation:

Herbs are the leaves.

Vegetables are the seeds.

Fruits are the seeds.

So spices are the only option left.

8 0

2 years ago

In today's experiment, Solutions A and B are prepared as follows.

hram777 [196]

Answer:

D. 0.160

Explanation:

The solution A is obtained adding 2.0mL of a solution of bromocresol green, 5.0mL of 1.60M HAc and 2.0mL of a solution of KCl. The solution is diluted to 50mL

That means the HAc is diluted from 5.0mL to 50.0mL, that is:

50.0mL / 5.0mL = 10 times.

And the final concentration of HAc must be:

1.60M / 10 times =

0.160M

Right answer is:

3 0

2 years ago