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Masja [62]
3 years ago
5

Suppose you increase your walking speed from 5m/s to 15m/s in a period of 1 s. What is your acceleration?

Physics
1 answer:
olchik [2.2K]3 years ago
7 0
Acceleration=change in velocity divided by change in time or a=\frac{\Delta v}{\Delta t}

we are given that it goes from 5m/s to 15m/s
\Delta v=v_f-v_0
in this case, \Delta v=15\frac{m}{s}-5\frac{m}{s}=10\frac{m}{s}

and the change in time or \Delta t is 1 second because this change occurs over a period of 1 second

so the acceleration is a=\frac{10\frac{m}{s}}{1s}=10\frac{m}{s^2}
the acceleration is 10\frac{m}{s^2}
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The trajectory of a projectile always ________________.
sattari [20]

Answer:

c) curves downward, below the initial velocity vector

Explanation:

A projectile is usually launched from a height, where it is launched with an initial velocity. From that point the gravitational force begins to act on the projectile causing it to decay. As time passes, the projectile advances but its height decreases. So its trajectory is curved downward, below the initial velocity vector.

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3 years ago
If fire needs oxygen to burn, where does the sun get oxygen if there is no oxygen in space?​
elena55 [62]

Answer:

through nuclear fusion

Explanation:

The burning of the sun is not chemical combustion. It is nuclear fusion. This combustion releases energy which we experience as the heat and light given off by the flame.

5 0
2 years ago
Read 2 more answers
A 12-kg hammer strikes a nail at a velocity of 8.5 m/s and comes to rest in a time interval of 8.0 ms. (A) What is the impulse g
dimulka [17.4K]

Answer:

102 kg.m/s

Explanation:

m = Mass of hammer = 12 kg

v = Final velocity = 8.5 m/s

u = Initial velocity = 0

t = Time taken = 8 ms

Force acting over a given amount of time or change in momentum is known as impulse.

Impulse

J=Ft\\\Rightarrow J=p_2-p_1\\\Rightarrow J=m(v-u)\\\Rightarrow J=12(8.5-0)\\\Rightarrow J=102\kg.m/s

Impulse given to the nail is 102 kg.m/s

6 0
3 years ago
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The soccer game begins with a ______ ______ in the center of the field
blagie [28]
It begins with a kick-off
6 0
3 years ago
Suppose a car travels 106 km at a speed of 28 m/s and uses 1.9 gals of gasoline in the process. Only 30% of the gasoline goes in
USPshnik [31]

Answer:

a) The magnitude of the force is 968 N

b) For a constant speed of 30 m/s, the magnitude of the force is 1,037 N

Explanation:

<em>NOTE: The question b) will be changed in other to give a meaningful answer, because it is the same speed as the original (the gallons would be 1.9, as in the original).</em>

Information given:

d = 106 km = 106,000 m

v1 = 28 m/s

G = 1.9 gal

η = 0.3

Eff = 1.2 x 10^8 J/gal

a) We can express the energy used as the work done. This work has the following expression:

W=F\cdot d

Then, we can derive the magnitude of the force as:

F=\frac{W}{d}=\frac{\eta\cdot (G\cdot Eff)}{d}=\frac{0.3*1.9*(1.8*10^8)}{106*10^3} =968\,N

b) We will calculate the force for a speed of 30 m/s.

If the force is proportional to the speed, we have:

F_2=F_1(\frac{v_2}{v_1} )=968(\frac{30}{28} )=968*1.0714=1,037\,N

6 0
3 years ago
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