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4 years ago

How do climate differences affect the movement at the Mariana Trench

Physics

1 answer:

vovangra [49]4 years ago

8 0

It pushes the currents to opposite sides

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sandra lives in a country located in the northern hemisphere she makes a sundial by erecting a pole vertically in her garden the

Arte-miy333 [17]

Answer:

Explanation:

The sun has rotated causing the shadow to reflect.

5 0

3 years ago

a plane travels 2.5 km at an angle of 35 degrees to the ground and then changes Direction and travels 5.2 km and an angle of 22

Bess [88]

We can solve for the resultant x and y components by using the sine and cosine functions.

resultant x = 2.5 cos 35 + 5.2 cos 22 = 6.87 km

resultant y = 2.5 sin 35 + 5.2 sin 22 = 3.38 km

The resultant displacement is calculated using hypotenuse equation:

displacement = sqrt (6.87^2 + 3.38^2)

displacement = 7.66 km

The resultant angle is:

θ = tan^-1 (3.38 / 6.87)

θ = 26.20°

Therefore the magnitude and direction is:

7.66 km, 26.20° to the ground

3 0

4 years ago

You hold a metal block of mass 40 kg above your head at a height of 2 m.

Kitty [74]

Answer:

The work done by gravity is 784 J.

Explanation:

Given:

Mass of the block is, $m=40\ kg$

Height to which it is raised is, $h=2\ m$

Acceleration due to gravity is, $g=9.8\ m/s^2$

Now, work done by gravity is equal to the product of force of gravity and the distance moved in the direction of gravity. So,

$\textrm{Work by gravity}=F_g\times h$

Force of gravity is given as the product of mass and acceleration due to gravity.

$\therefore F_g=mg=40\times 9.8=392\ N$ . Now,

$\textrm{Work by gravity}=F_g\times h=392\times 2=784\ J$

Therefore, the work done by gravity is 784 J.

5 0

3 years ago

A cat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the rid

ioda

<span>Radius = 4.6 m
Time for one complete rotation t = 5.5 s.
Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
Force of the cat Fc = 6m, m being the mass.
Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116 So coefficient of static friction = 0.6116</span>

4 0

3 years ago

A person hits a tennis ball with a mass of 0.058 kg against a wall.

horrorfan [7]

Explanation:

Mass of the ball, m = 0.058 kg

Initial speed of the ball, u = 11 m/s

Final speed of the ball, v = -11 m/s (negative as it rebounds)

Time, t = 2.1 s

(a) Let F is the average force exerted on the wall. It is given by :

$F=\dfrac{m(v-u)}{t}$