Answer:
0.58 L
Explanation:
For this problem we need to simply use the ideal gas equation to create a proportional comparison for the initial information to the final information.
(P_1 * V_1) / T_1 = (P_2 * V_2) / T_2
Using this, we can solve for V_2 to find the new volume of the gas once pressure and temperature changes.
(P_1 * V_1) * T_2 / T_1 = (P_2 * V_2)
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
Consider our givens:
P_1 = 110atm
T_1 = 303K
V_1 = 2L
P_2 = 440atm
T_2 = 353K
Now we simply plug in these values to the equation to find the new volume, V_2.
(P_1 * V_1) * T_2 / (T_1 * P_2) = V_2
(110atm * 2L) * 353K / (303K * 440atm) = V_2
77660 atm*L*K / 133320 K*atm = V_2
0.583 L = V_2
Hence, the new volume is 0.583 L.
Cheers.
