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LenaWriter [7]
3 years ago
11

An alkyne will always have at least one

Chemistry
2 answers:
hammer [34]3 years ago
4 0
A) Triple bond. Have a nice day. :)

Eduardwww [97]3 years ago
3 0
An alkyne will always have at least one triple bond. Hopefully this helps! :)
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The number of proton, neutrons and electrons in oxygen atom
Ksenya-84 [330]

Answer:

in an oxygen atom there are:

protons:8

electrons:8

neutrons:8

Explanation:

this is because the atomic number of oxygen is 8 and that is the proton number and the electron number is the same as the atomic number

4 0
2 years ago
The molecular weight of NaCl is 58.44 grams/mole. If you had a 1.0 molar solution (1.0 M), you would have to put 58.44 g of salt
Andre45 [30]

Answer:

5,844 grams of NaCl

Explanation:

Knowing the molecular weight 58,44 g/mole and saying 1 molar solution is 58,44 of NaCl in 1 liter of solution. 100 mL means 10% of the whole solution then we are going to have 10% of NaCl

58,44 x 0,1 = 5,844 grams of NaCl

7 0
3 years ago
How many atoms, ions, or molecules are in a 1 molar solution?
Nezavi [6.7K]

Molarity refers to moles/ L. This indicates the concentration of a solution containing solute and solvent.

1 molar solution contains 1 mole of solute in 1 L of solvent.

According to Avogadro's number, 1 mole of a substance contains 6.023 x 10^23 molecules, atoms, or ions.

For this reason, 6.023 x 10^23 atoms, ions, or molecules are in a molar solution.

7 0
2 years ago
If the distance between London and New York is 3600 miles, how long would you
Tju [1.3M]

Answer:

3 hours

Explanation:

s=d/t

1200=3600/t

3600/1200=t

t=3

3 0
2 years ago
Which of the following 0.820 M solutions would have the greatest colligative effect?
eimsori [14]

Answer:

K3PO4

Explanation:

Recall that colligative properties depends on the number of particles present. The greater the number of particles present, the greater the degree of colligative properties of the solution. Let us look at each option individually;

SrCr2O7-------> Sr^2+ + Cr2O7^2- ( 2 particles)

C4H11N (not ionic in nature hence it can not dissociate into ions)

K3PO4-------> 3K^+ + PO4^3- (4 particles)

Rb2CO3-------> 2Rb^+ + CO3^2- (3 particles)

Hence K3PO4 has the greatest number of particles and will display the greatest colligative effect.

8 0
3 years ago
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