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LenaWriter [7]
3 years ago
11

An alkyne will always have at least one

Chemistry
2 answers:
hammer [34]3 years ago
4 0
A) Triple bond. Have a nice day. :)

Eduardwww [97]3 years ago
3 0
An alkyne will always have at least one triple bond. Hopefully this helps! :)
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Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. C2H6 + O2 → CO2 + H2O
fenix001 [56]
Step 1: Write the unbalanced equation,

                                 C₂H₆  +  O₂    →    CO₂  +  H₂<span>O

There are 2 C at left hand side and 1 carbon at right hand side. So, multiply CO</span>₂ by 2 to balance C atoms at both side. So,

                                 C₂H₆  +  O₂    →   2 CO₂  +  H₂O

Now, count number of H atoms at both sides. There are 6 H atoms at left hand side and 2 at right hand side. Multiply H₂O by 3 to balance H atoms.


                                 C₂H₆  +  O₂    →   2 CO₂  +  3 H₂O

At last, balance O atoms. There are 2 O atoms at left hand side and 3 O atoms at right hand side. Multiply O₂ with 1.5 (i.e. 3/2) to balance O atoms. i.e.

                                 C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O

Hence, the equation is balanced. If you want to make equation fraction free then multiply all equation with 2. i.e.

                           ( C₂H₆  +  3/2 O₂    →   2 CO₂  +  3 H₂O ) × 2

                                2 C₂H₆  +  3 O₂    →   4 CO₂  +  6 H₂O
5 0
3 years ago
Read 2 more answers
The substances in a chemical reaction that are combined or separated to form new substances are the _______.
katen-ka-za [31]
Reactant/ Reagents and Products
6 0
3 years ago
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A sample of nitrogen gas has a volume of 478 cm3 and a pressure of 104.1 kPa. What volume would the gas occupy at 88.2 kPa if th
nadezda [96]

<span>1.    </span>To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

V2 = P1 x V1 / P2

 V2 = 104.1 x 478 / 88.2

<span> V2 =564.17 cm^3</span>

6 0
3 years ago
Read 2 more answers
which pair shares the same empirical formula. c2h2 and c6h6, c2h2 and c2h4, ch2 and c6h6, ch and c2h4
olasank [31]

Answer:

Answer: CH₃ and C₂H₆ have same empirical formula.

Explanation:

it just compares in that it its the same

7 0
3 years ago
Which elements can have expanded octets?
PSYCHO15rus [73]

Answer:

Sulfur, phosphorus, silicon, and chlorine are common examples of elements that form an expanded octet.

Explanation:

Phosphorus pentachloride (PCl5) and sulfur hexafluoride (SF6) are examples of molecules that deviate from the octet rule by having more than 8 electrons around the central atom

7 0
2 years ago
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