I do believe the answer is A. Hope this helps.
Here is the answer for your question which the mole of chlorine is 1.34
➢225 mL of solution containing<span> 0.486 </span>mole<span> of solute </span>mol<span> HCl. Use </span>molarity<span> as a conversion factor.</span>Mol<span> HCl = 2.5 L soln x 0.10 </span>mol<span> HCl by diluting 25.0 mL of 6.00 M HCl to a </span>total volume<span> of 50.0 Note: Vc and Vd do not </span>have<span> to be ➢The mass of MgCl2 in a </span>2.75 mole<span> sample 3.447 g of </span>CO2<span> and 1.647 g of H2O.</span>
