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ira [324]
3 years ago
9

Silver nitrate is reacted with magnesium bromide and two products are formed.

Chemistry
1 answer:
Sati [7]3 years ago
8 0

Answer:

<u><em>The correct answer is : </em></u>

         a silver nitrate solution (AgNO3) is mixed with a solution of magnesium bromide (MgBr2). The balanced reaction would be: 2 AgNO3(aq) + MgBr2 --> 2 AgBr + Mg(NO3)2

<u><em>the last one </em></u>

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7 0
4 years ago
Write the complete ionic equations, spectator ions and net ionic equation for the following.
gizmo_the_mogwai [7]

Answer:

Explanation:

1) ZnBr₂ (aq) + AgNO₃ (aq)

Chemical equation:

 ZnBr₂ (aq) + AgNO₃ (aq)  →Zn(NO₃)₂(aq) + AgBr(s)

Balanced chemical equation:

ZnBr₂ (aq) + 2AgNO₃ (aq)  →Zn(NO₃)₂(aq) + 2AgBr(s)

Ionic equation:

Zn²⁺(aq) + Br₂²⁻ (aq) + 2Ag⁺ (aq)+ 2NO⁻₃ (aq)  → Zn²⁺(aq) +(NO₃)₂²⁻(aq) + 2AgBr(s)

Net ionic equation:

Br₂²⁻ (aq) + 2Ag⁺ (aq)   →    2AgBr(s)

The Zn²⁺((aq) and NO⁻₃ (aq) are spectator ions that's why these are not written in net ionic equation. The AgBr can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

2) HgCl₂ (aq) + KI (aq)  →

Chemical equation:

HgCl₂ (aq) + KI (aq)  → KCl + HgI₂

Balanced chemical equation:

HgCl₂ (aq) + 2KI (aq)  → 2KCl(aq) + HgI₂(s)

Ionic equation:

Hg²⁺(aq)  + Cl₂²⁻  (aq) + 2K⁺(aq) + 2I⁻ (aq)  →  HgI₂ (s) + 2K⁺(aq) + 2Cl⁻ (aq)

Net ionic equation:

Hg²⁺(aq)  + 2I⁻ (aq) →   HgI₂ (s)

The Cl⁻ ((aq)  and K⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The HgI₂ (s) can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

 

3) Ca(OH)₂ (aq) + Na₂SO₄ (aq)

Chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + NaOH(aq)

Balanced chemical equation:

Ca(OH)₂ (aq) + Na₂SO₄ (aq)  →   CaSO₄(s) + 2NaOH(aq)

Ionic equation:

Ca²⁺(aq)  + OH₂²⁻  (aq) + 2Na⁺(aq) + SO₄²⁻ (aq)  →   CaSO₄(s) + 2Na⁺(aq) + 2OH⁻ (aq)

Net ionic equation:

Ca²⁺(aq)   + SO₄²⁻ (aq)  →   CaSO₄(s)

The OH⁻ ((aq)  and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The CaSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.

4 0
3 years ago
Construct a simulated 1H NMR spectrum, including proton integrations, for CH3OC(CH2OCH3)3 (see Hint). Drag the appropriate split
CaHeK987 [17]

Answer:

The drawing of the structure is found in diagram 1 of the attached figure.

Explanation:

Diagram 1 shows that three different types of protons are found in the structure. The nine hydrogen atoms have a similar behavior, the six hydrogen atoms also have a similar behavior and finally, the three hydrogen atoms adjacent to oxygen have a similar behavior. The number of peaks are as follows:

9H = singlet peak = between 3 and 4 ppm

6H = singlet peak = 4 ppm

3H = singlet peak = 3 ppm.

The 9 protons are around 3.5 ppm and the 6 hydrogen atoms show a peak at 4 ppm, and finally, the 3 protons have a peak around 3 ppm. Therefore, the corresponding drawing can be seen in diagram 2.

4 0
3 years ago
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andreev551 [17]

Answer:

conditioning

trial-and-error learning

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a bond to a individual or object shortly after birth or hatching

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Explanation:

3 0
3 years ago
Calcula la densidad de un cuerpo que tiene la masa de 12g y un volumen de 3cm^3 dar el resultado en unidades del SI
kvv77 [185]

The density is 4 g/cm³ or 4000 kg/m³.

Density = mass/volume = 12 g/3 cm³ = 4 g/cm³

The measurement of 4 g/cm³ is already in <em>SI units</em>.  

In SI <em>bas</em>e units,  

Density = (4 g/1 cm³) × (1 kg/1000 g) × (100 cm/1 m)³ = 4000 kg/m³


3 0
3 years ago
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