Ask question

Ask question

All categories

3 years ago

13

What is hte type of mixture whose components are evenly distrbuted out word wise?

1 answer:

Bumek [7]3 years ago

3 0

The answer is heterogeneous mixture.

Hope this helps

You might be interested in

Which pair of ions can form an ionic bond with each other and why? A.Cu and Ag; They are both metal ions.B. S and O; They have l

kap26 [50]

Opposite pairs form ionic bonds, due to this the answer is D - Li and Br; They have unlike charges.

5 0

3 years ago

Read 2 more answers

Nena___her hair every morning. <br>A.BRUSH <br> B.BRUSHES <br>C.BRUSED <br>D. WILLBRUSHED

coldgirl [10]

Answer:

I'm pretty sure it's A. BRUSH

Explanation:

If I'm wrong let ne know please

7 0

3 years ago

Read 2 more answers

What is a covalent bond?

Natali5045456 [20]

A bond between two atoms that SHARE electrons

4 0

3 years ago

In the lewis structure of ch3oh, how many bonding pairs of electrons are there?

zysi [14]

Answer:
There are five <span>bonding pairs of electrons in Methanol.

Explanation:
Those electron pairs which are being shared between two atoms in molecule are called as bonding pair electrons. While, those electron pairs which are not involved in bond formation and are not shared between two atoms are called as Non-Bonding electron pairs.
In molecule of Methanol as shown below, it can be seen that carbon atom is forming four bonds with three hydrogen atoms and one oxygen atom by sharing four electron pairs and oxygen is forming two bonds, one with carbon atom and one with hydrogen atom. There are two lone pair of electrons present on oxygen atom which are not taking part in and formation.</span>

8 0

4 years ago

A chemist must prepare 800.0mL of sodium hydroxide solution with a pH of 12.10 at 25°C. She will do this in three steps: Fill a

AnnZ [28]

Answer:

0.42 g

Explanation:

<u>We have: </u>

pH = 12.10 (25 °C)

V = 800.0 mL = 0.800 L

To find the mass of sodium hydroxide (NaOH) we can use the pH:

$14 = pH + pOH$

$pOH = 14 - pH = 14 - 12.10 = 1.90$

$pOH = -log ([OH^{-}])$

$[OH]^{-} = 10^{-pOH} = 10^{-1.90} = 0.013 M$

Now, we can find the number of moles (η) of OH:

$\eta = ([OH]^{-})*V = 0.013 mol/L * 0.800 L = 1.04 \cdot 10^{-2} moles$

Since we have 1 mol of OH in 1 mol of NaOH, the number of moles of NaOH is equal to 1.04x10⁻² moles.

Finally, with the number of moles we can find the mass of NaOH:

$m = \eta * M$

<em>Where M is the molar mass of NaOH = 39.9 g/mol </em>

$m = 1.04 \cdot 10^{-2} moles * 39.9 g/mol = 0.42 g$

Therefore, the mass of sodium hydroxide that the chemist must weigh out in the second step is 0.42 g.

I hope it helps you!

3 0

3 years ago