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Andre45 [30]
3 years ago
13

Suppose figure A underwent a dilation to produce figure B. Are figure A and figure B similar?

Mathematics
1 answer:
TEA [102]3 years ago
4 0

Answer:

<em>Yes, because even though their side lengths are different, their internal angles are the same.</em>

<em />

Step-by-step explanation:

You might be interested in
In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch.
kirza4 [7]

Answer:

<h2>7.4inches</h2>

Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

According to the rule;

\frac{u}{sinU} =  \frac{v}{sinV} = \frac{w}{sinW}\\\frac{u}{sinU} = \frac{w}{sinW}

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in

The length of u is 7.4inches to nearest 10th of an inch

6 0
3 years ago
I only need help with the second part of this question. please can you help?
matrenka [14]

13,822 to one significant figure is 10,000

623 to one significant figure is 600

14 to one significant figure is 10

10,000 times 600 = 6,000,000

6,000,000/10 = 600,000

4 0
3 years ago
Eight computers are on a network, and each computer is linked to every other computer. How many such connections are there in to
MrRissso [65]
Hope this helps but I think the answer is 3 connections. But I am not sure.Here is how I got my answer since they said every other computer has a connection then it should be that 1 and 3,3and 5,and 5 and 7 have a connection.That is 3 connections in total.
3 0
3 years ago
Help me with this please
tankabanditka [31]

Answer:

  73/39

Step-by-step explanation:

The slope of the given line is the coefficient of x in the given equation, which we recognize as being in slope-intercept form.

The slope of the perpendicular line will be the opposite reciprocal of this:

  -1/(-39/73) = 73/39 . . . . slope of the perpendicular line

3 0
2 years ago
The bass in Clear Lake have weights that are normally distributed with a mean of 2.2 pounds and a standard deviation of 0.6 poun
Papessa [141]

Answer:

Step-by-step explanation:

(a) What is the mean fish weight of your catch of 6? Round your answer to 1 decimal place.  =Total weight/no of fish in sample

_\frac{15.9}{6} =2.65_____ pounds

(b) If 6 bass are randomly selected from Clear Lake, find the probability that the mean weight is greater than the mean of those you caught. Round your answer to 4 decimal places.

___P(mean >2.65)=P(Z>\frac{2.65-2.2}{\frac{0.6}{\sqrt{0.6} } } \\=P(Z>0.18)\\=0.5-0.0714=0.4286_____

Sample mean follows a normal distribution with mean = 2.2 and std error = 0.6/sqrt 6

(c) Which statement best describes your situation?

_____ This is not particularly unusual because the mean weight of your fish is only 0.5 pounds above the population average.

3 0
3 years ago
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