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mariarad [96]
3 years ago
13

Consider the two functions. Which statement is true?

Mathematics
2 answers:
MrRissso [65]3 years ago
6 0

Answer:

Where are the functions?

Step-by-step explanation:

nikdorinn [45]3 years ago
4 0

Answer:

the ANSWER IS D

Step-by-step explanation:

Function 2 has a greater rate of change by  

1

2

Function 1 has a slope of  

5

2

and Function 2 has a slope of 3.

thus,

3 -  

5

2

=  

6

2

-  

5

2

=  

1

2

You might be interested in
Find the limit (enter 'DNE' if the limit does not exist)
vaieri [72.5K]

Answer:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)=2

Step-by-step explanation:

We need to first simplify the expression using rationalization(i.e. if a square root term exists in the denominator, then multiply and divide the whole expression by the denominator(but the change the sign of its middle term))

here, we need to find:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\right)

first we'll rationalize our expression:

\dfrac{-2x^2-6y^2}{\sqrt{-2x^2-6y^2+1}-1}\left(\dfrac{\sqrt{-2x^2-6y^2+1}+1}{\sqrt{-2x^2-6y^2+1}+1}\right)

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{(\sqrt{-2x^2-6y^2+1}+1)^2-(1)^2}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-2x^2-6y^2+1-1}

\dfrac{-(2x^2+6y^2)(\sqrt{-2x^2-6y^2+1}+1)}{-(2x^2+6y^2)}

\sqrt{-2x^2-6y^2+1}+1

this is our simplified expression, now we can apply our limits:

\lim\limits_{(x,y)\rightarrow(0,0)}\left(\sqrt{-2x^2-6y^2+1}+1\right)

\sqrt{-2(0)^2-6(0)^2+1}+1

1+1

2

the limit does exists and it is 2.

5 0
3 years ago
I don't get it plz help
Salsk061 [2.6K]
Just use the order of operations. PEMDAS, parentheses, exponents, multiplication, division, addition and subtraction.

In the first problem 2 + 6*3^2, there are no parentheses, so next would be exponents.
There is an exponent so you do that first.
3^2 = 9

Now we have 2 + 6*9
Multiplication is next and it is in the problem, so we do 6*9 = 54
So now we have 2 + 54 which equals 56.
6 0
3 years ago
Read 2 more answers
In ΔLMN, the measure of ∠N=90°, the measure of ∠M=70°, and NL = 74 feet. Find the length of MN to the nearest tenth of a foot.
Zina [86]

Answer:26.9 feet

Step-by-step explanation:

SOH-CAH-TOA

\tan M = \frac{\text{opposite}}{\text{adjacent}}=\frac{74}{x}

tanM=

adjacent

opposite

​

=

x

74

​

\tan 70=\frac{74}{x}

tan70=

x

74

​

x\tan 70=74

xtan70=74

Cross multiply.

\frac{x\tan 70}{\tan 70}=\frac{74}{\tan 70}

tan70

xtan70

​

=

tan70

74

​

Divide each side by tan 70.

x=\frac{74}{\tan 70}=26.9338\approx 26.9\text{ feet}

x=

tan70

74

​

=26.9338≈26.9 feet

Type into calculator and roundto the nearest tenth of a foot.

L

M

N

74

26.9

(opposite of ∠M)

(adj. to ∠M)

(hypotenuse)

70°

5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIESTTTT :)
Taya2010 [7]

Answer:

Yes, these triangles are congruent

∠E≅∠M

Step-by-step explanation:

Yes, these triangles are similar.

<em>Proof:</em>

Each side in LNM is 1\frac{2}{3} times longer than the sides in GFE

30/18 = 1\frac{2}{3}

25/15=1\frac{2}{3}

20/12 = 1\frac{2}{3}

According CPCTC (corresponding parts of congruent triangles are congruent), angle E is similar to angle M.

Hope this helps :)

Have a good day!

4 0
2 years ago
If triangle VWX and triangle NOP are similar. If mV=44 degrees and mP=66 degrees. What is mW?
77julia77 [94]
I think the answer is mW = 70 degrees
4 0
3 years ago
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