$A\cup B=A\cup(A-B)\\\\A\ and\ A-B\ are\ disjoint\ that\ means\ there\ is\ no\ common\ element\ in\ these\ two.\\\\n(A\cup B)=n(B\cup(A-B))\\\\n(A\cup B)=n(B)+n(A-B)\ \ \ \ \ \ \ as\ for\ disjoint\ set\ P,Q\ n(P\cup Q)=n(P)+n(Q)\\\\(n(P-Q)=n(P)-n(P\cap Q))\\\\n(AUB)=n(B)+n(A-B)\\\\n(AUB)=n(B)+n(A)-n(A\cap B)\\\\n(AUB)=n(A)+n(B)-n(A\cap B)\\\\Hence\ given\ statement\ is\ true$

4 0

3 years ago

Is (8, 3) a solution to the system?<br> - 2 + 4y = 4<br> - 2 + 3y = 1

AURORKA [14]

Answer:

No, it's not a solution.

Step-by-step explanation:

-2 + 4(3) = 4

-2 + 12 = 10

-2 + 3(3) = 1

-2 + 9 = 7

3 0

2 years ago

(Pls help i need this ASAP I got 10 min left) Is Figure A’B’C’D’ a reflection of Figure ABCD? Explain.

gtnhenbr [62]

Answer:

yes it's a refelction over the line f (C)

Step-by-step explanation:

so c is correct

8 0

2 years ago

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