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4 years ago

How do you write x is great than 9?

Mathematics

2 answers:

Andrej [43]4 years ago

8 0

You write it like this x>9

valentina_108 [34]4 years ago

5 0

X>9 is how you would write X is greater than 9.

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F(x)= 6x-7 g(x)=6x+7, f(g(x))= and g(f(x))=

horrorfan [7]

Can u take a picture please?

6 0

3 years ago

What is the rate of change for the sequence shown below. (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

Nataly [62]

Answer:

0.5

Step-by-step explanation:

The given ordered pairs are: (1,2) (2,2.5) (3,3) (4,3.5) (5,4)

The corresponding sequence is :

2,2.5,3,3.5, 4,....

We can see that there is a common difference of d=0.5.

Better still we could use the slope formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

We substitute the point (1,2) and (2,2.5).

The rate of change of this sequence is:

$m = \frac{2.5 - 2}{2 - 1} = \frac{0.5}{1} = 0.5$

5 0

4 years ago

What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

Now, using the ALGEBRAIC IDENTITY:

$a^2 - b^2 = (a-b)(a+b)$

Comparing this with the above expression, we get

$x^2 - 4 = 0 = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0$

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2) = 0 ⇒ x = 2

and if ( x + 2) = 0 ⇒ x = -2

Hence, for $x^2 - 4 = 0$ , x = 2, or x = - 2.

4 0

4 years ago

Read 2 more answers

The circumference of a circle with a diameter 1.8cm take pie to be 3.142

Gennadij [26K]

The formula to get the circumference is 2πr, π being pi and r being your radius.

Your r is 0.9 since the radius is half the diameter.

2πr = 2 x 3.142 x 0.9

= 5.6556cm

≈ 5.7cm

4 0

3 years ago

are any two regular polygons similar. The area of the smaller figure is about 390 cm^2. choose the best estimate of the area of

galben [10]

Answer:

The best estimate of the area of the larger figure is $693\ cm^{2}$

Step-by-step explanation:

step 1

<em>Find the scale factor</em>

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x-----> the corresponding side of the larger figure

y-----> the corresponding side of the smaller figure

$z=\frac{x}{y}$

we have

$x=12\ cm$

$y=9\ cm$

substitute

$z=\frac{12}{9}=\frac{4}{3}$ -----> the scale factor

step 2

<em>Find the area of the larger figure</em>

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x-----> the area of the larger figure

y-----> the area of the smaller figure

$z^{2}=\frac{x}{y}$

we have

$z=\frac{4}{3}$

$y=390\ cm^{2}$

substitute and solve for x

$(\frac{4}{3})^{2}=\frac{x}{390}$

$(\frac{16}{9})=\frac{x}{390}$

$x=390*16/9=693.33\ cm^{2}$

4 0

3 years ago