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Gennadij [26K]
3 years ago
10

How many grams of lactic acid (C,H,O) are in 1 liter of a 0.5M solution of lactic acid?

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

a mole of lactic acid = 90 g

a 0.5 M solution would require 1/2 mol or 45 g

Explanation:

The molecular mass is 90 d, the combined atomic masses of its atoms.

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How many moles of NH3 can you make from 6.20 moles of N2?
german
4 I think


$ hope it welp
4 0
3 years ago
Read 2 more answers
Balance this equation C2H4 + O2 + CO2 + H2O ​
LenKa [72]

Answer: C₂H₄+3 O₂= 2 CO₂+ 2 H₂O

Explanation:

5 0
3 years ago
If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol
igomit [66]

Answer:

\Delta _RH=4x10^{-3}\frac{kJ}{mol}

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}

Best regards.

5 0
3 years ago
Mercury may have lost part of its mantle and crust to a _______ leaving it with a large, metal _______.
igomit [66]
<h2>Giant impact and metalcore.</h2>

Explanation :

  • Mercury has a large core of liquid metal.
  • The metal core is of iron metal.
  • The core is surrounded by a mantle which is made up of silica and a solid outer crust.
  • In the case of Mercury, the total core percentage is 42% of the planet while the Earth's core is only 17% of the planet.
  • Mercury has lost part of its mantle and crust that left the mercury with a large metal core.

3 0
3 years ago
If the density of gold is 19.3 g/cm3 what would be the volume of 550 g of gold?​
RUDIKE [14]

Answer:

28.497 cm3

Explanation:

Formula

D=m/v

Given data:

density = 19.3g/cm3

mass = 550 g

Now we will put the values in formula:

V=m/d

V=550 g/ 19.3 g/cm3  = 28.497 cm3

So the volume of gold is 28.497 cm3.

7 0
4 years ago
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