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1 year ago

15

You’re sitting at a car race and the cars sound differently when they approach as opposed to when they are moving away. Why migh

t this be true? Explain in detail.

1 answer:

bulgar [2K]1 year ago

5 0

Answer:

I have no clue this qestion is kinda stumping but it a really good question it got me thinking but i don't know if there is a right answer

Explanation:

I don't know

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Write and balance the equation for the combination of ammonia gas with solid copper (II) oxide to produce copper metal, nitrogen

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Explanation :

The balanced chemical reaction will be,

$3CuO(s)+2NH_3(g)\rightarrow 3Cu(s)+N_2(g)+3H_2O(l)$

By the stiochiometry, 3 moles of solid copper(II)oxide react with 2 moles of ammonia gas to give 3 moles of copper metal, 1 mole of nitrogen gas and 3 moles of liquid water.

The states of matter of each elements and compound is,

Copper(II)oxide is in solid state

Ammonia is in gaseous state

Copper metal is in solid state

Nitrogen is in gaseous state

Water is in liquid state

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Is saliva a element compound or mixture

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mixture

Explanation:

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In a far-off galaxy, an astronomer observes a moon orbiting a planet. The moon stays in orbit because of the planet’s gravity. W

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For each of the following nuclei, determine the binding energy per nucleon (in MeV). (For all masses, keep six places beyond the

garik1379 [7]

Answer: (a) BE = 1.112 MeV

(b) BE = 7.074 MeV

(c) BE = 7.767 MeV

(d) BE = 8.112 MeV

Explanation: Binding energy per nucleon is the average energy necessary to remove a proton or a neutron from the nucleus of an atom. It is mathematically defined as:

$BE = \frac{\Delta m.c^{2}}{A}$

Where

Δm is a difference in mass known as <u><em>mass</em></u><em> </em><u><em>defect</em></u>

A is atomic mass of an atom.

Mass Defect is determined by:

$\Delta m =Zm_{p}+(A-Z)m_{n} - m_{nuc}$

where:

Z is atomic number

$m_{p}$ is mass of proton

$m_{n}$ is mass of neutron

$m_{nuc}$ is mass of the nucleus

Mass of proton is 1.007825u.

Mass of neutron is 1.008665u.

The unit u is equal to 931.5MeV/c².

(a) 2H(deuterion): Given: Z = 1; A = 2; $m_{nuc}$ = 2.014102u

$\Delta m =1(1.007825)+1(1.008665) -2.014102$

$\Delta m =0.002388u$

$BE = \frac{0.002388.c^{2}}{2}.931.5\frac{MeV}{c^{2}}$

BE = 1.112MeV

(b) 4He (Helium): Given: Z = 2; A = 4; $m_{nuc}$ = 4.002603

$\Delta m =2(1.007825)+2(1.008665) -4.002603$

$\Delta m =0.030377u$

$BE = \frac{0.030377.c^{2}}{4}.931.5\frac{MeV}{c^{2}}$

BE = 7.074MeV

(c) 18O (Oxygen): Given: Z = 8; A = 18; $m_{nuc}$ = 17.999160

$\Delta m =8(1.007825)+10(1.008665) -17.999160$

$\Delta m =0.15009u$

$BE = \frac{0.15009.c^{2}}{18}.931.5\frac{MeV}{c^{2}}$

BE = 7.767MeV

(d) 23Na (Sodium): Given: Z = 11; A = 23; $m_{nuc}$ = 22.989767

$\Delta m =11(1.007825)+12(1.008665) -22.989767$

$\Delta m =0.200288u$

$BE = \frac{0.200288.c^{2}}{23}.931.5\frac{MeV}{c^{2}}$

BE = 8.112MeV

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