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2 years ago

15

You’re sitting at a car race and the cars sound differently when they approach as opposed to when they are moving away. Why migh

t this be true? Explain in detail.

1 answer:

bulgar [2K]2 years ago

5 0

Answer:

I have no clue this qestion is kinda stumping but it a really good question it got me thinking but i don't know if there is a right answer

Explanation:

I don't know

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(a) Calculate the mass of CaCl2·6H2O needed to prepare 0.125 m CaCl2(aq) by using 500. g of water. (b) What mass of NiSO4·6H2O m

Alinara [238K]

Answer:

(a) 13.7 g.

(b) 28.91 g.

Explanation:

molality (m) is the no. of moles of solute dissolved in 1.0 kg of solvent.

∴ m = (no. of moles of solute)/(mass of water (kg))

<em>∴ m = (mass/molar mass of solute)/(mass of water (kg)).</em>

<em />

<u><em>(a) Calculate the mass of CaCl₂·6H₂O needed to prepare 0.125 m CaCl₂(aq) by using 500. g of water.</em></u>

∵ m = (mass/molar mass of CaCl₂·6H₂O)/(mass of water (kg)).

m = 0.125 m, molar mass of CaCl₂·6H₂O = 219.0757 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of CaCl₂·6H₂O / 219.0757 g/mol)/(0.5 kg).

∴ mass of CaCl₂·6H₂O = (0.125 m)(219.0757 g/mol)(0.5 kg) = 13.7 g.

<u><em>(b) What mass of NiSO₄·6H₂O must be dissolved in 500. g of water to produce 0.22 m NiSO₄(aq)?</em></u>

∵ m = (mass/molar mass of NiSO₄·6H₂O)/(mass of water (kg)).

m = 0.22 m, molar mass of NiSO₄·6H₂O = 262.84 g/mol, mass of water = 500.0 g = 0.5 kg.

∴ 0.125 m = (mass of NiSO₄·6H₂O / 262.84 g/mol)/(0.5 kg).

∴ mass of NiSO₄·6H₂O = (0.22 m)(262.84 g/mol)(0.5 kg) = 28.91 g.

6 0

4 years ago

What is the concentration of NaCl in a solution if titration of 15.00 mL of the solution with 0.2503 M AgNO3 requires 20.22 mL o

Nina [5.8K]

Answer:

The concentration of NaCl = 0.3374 M

Explanation:

Given :

Molarity of AgNO₃ = 0.2503 M

Volume of AgNO₃ = 20.22 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 20.22×10⁻³ L

Molarity of a solution is the number of moles of solute present in 1 L of the solution.

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

The formula can be written for the calculation of moles as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Thus,

$Moles\ of\ AgNO_3 =Molarity \times {Volume\ of\ the\ solution}$

$Moles\ of\ AgNO_3 =0.2503 \times {20.22\times 10^{-3}}\ moles$

$Moles\ of\ AgNO_3 = 5.0611 \times 10^{-3} moles$

The chemical reaction taking place:

$AgNO_3_(aq) + NaCl_(aq) \rightarrow AgCl_(s) + NaNO_3_(aq)$

According to reaction stoichiometry:

<u>1 mole</u> of AgNO₃ reacts with <u>1 mole</u> of NaCl

Thus,

5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl

Thus, moles of NaCl required = 5.0611×10⁻³ moles

Volume of NaCl required = 15.00 mL

The conversion of mL into L is shown below:

$1 mL= 10^{-3} L$

Thus, volume of the solution = 15.00×10⁻³ L

Applying in the formula of molarity as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Molarity\ of\ NaCl=\frac{5.0611\times 10^{-3}}{15.00\times 10^{-3}}$

$Molarity\ of\ NaCl= 0.3374 M$

<u>Thus, the concentration of NaCl = 0.3374 M</u>

6 0

3 years ago

Mercury thermometers work because mercury ____ when it is warmed

kap26 [50]

Mercury expands when it is heated. This process is called thermal expansion.

5 0

3 years ago

When a substance is in the process of changing phases states of matter what happens to the temperature

Reptile [31]

Answer:

Temperature stays constant.

Explanation:

During a phase change, the temperature does not change. Temperature will only change when a phase change is completed.

8 0

3 years ago

A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student

BabaBlast [244]

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

Moles of sodium chloride = $\frac{39.7 g}{58.5 g/mol}=0.6786 mol$

According to reaction, 2 moles of NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

$\frac{1}{2}\times 0.6786 mole=0.3393 mol$

Mass of 0.3393 moles of chlorine gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.

5 0

4 years ago