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Vlada [557]
2 years ago
15

You’re sitting at a car race and the cars sound differently when they approach as opposed to when they are moving away. Why migh

t this be true? Explain in detail.
Chemistry
1 answer:
bulgar [2K]2 years ago
5 0

Answer:

I have no clue this qestion is kinda stumping but it a really good question it got me thinking but i don't know if there is a right answer

Explanation:

I don't know

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There are 43.2 g of carbon to 14.4 g of hydrogen in a sample of methane (CH4). What percent of 37.8 g of methane is carbon?
EastWind [94]

Using the law of constant proportions  which says that within the same compound, elements exist in fixed ratios. 

Therefore; we can use the ratio of total mass to the mass of carbon, to determine the amount of carbon in another sample.

Mass C / Mass CH4 = Mass C / Mass CH4

43.2 g / 57.6 g = Mass C / 37.8 g

Mass C = 37.8 g × 43.2 g / 57.6 g 

              = 28.35 g

Hence; the percentage of carbon will be; 

=(28.35/ 37.8 )× 100%

= 75 % 

Thus; 75% of 37.8 g of methane is carbon

8 0
4 years ago
Which of the following is an important application of hydrogen bonding?
lakkis [162]

Answer:

Holding of DNA together

Explanation:

4 0
3 years ago
Read 2 more answers
Structure for reductive ozonolysis of 3,5-dimethyl-4-octene​
brilliants [131]

Answer:

Scheme is Attached.

When 3,5 dimethyl-4- octene is react with ozone two products are obtain.

2-Methyl butanal and 2 pentanon.

The complete reaction is given in attached file.

3 0
3 years ago
In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How
____ [38]

Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

  • Ca: 40 g/mole
  • F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=\frac{0.0016 grams*1 mole}{78 grams}

moles=2.05*10⁻⁵

<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF_{2}=\frac{1000 mL*1g}{1mL}

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=\frac{1000 grams*1 mole}{78 grams}

moles=12.82

<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>

5 0
3 years ago
What’s the temperature at the boiling and freezing point of water in fanrenheit
Dominik [7]

Answer:

Boiling is 212* Freezing is 32*

Explanation:

It simple facts

5 0
3 years ago
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