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3 years ago

Who performed the oil-drop experiment?

Chemistry

2 answers:

evablogger [386]3 years ago

7 0

In the year 1909, Robert A. Millikan and Harvey Fletcher performed the oil drop experiment.

faltersainse [42]3 years ago

7 0

Answer:

Robert Millikan

Explanation:

(APEX)

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PV = nRT. If P = 1 atm, V = 5.0 liter, R = 0.0821 L.atm/mol.K, and T = 293 K; what is the value of n?

Leya [2.2K]

Answer:

n = 0.207 mole

Explanation:

We have,

P = 1 atm

V = 5 liter

R = 0.0821 L.atm/mol.K

T = 293 K

We need to find the value of n. The relation is as follows :

PV = nRT

Solving for n,

$n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 5}{0.0821 \times 293}\\\\n=0.207\ \text{mol}$

So, the value of n is 0.207 mol.

6 0

3 years ago

A 25 liter gas cylinder contains 10 mole of carbon dioxide. Calculate the pressure, in atm, of the gas at 325K.

Arada [10]

<u>Answer:</u> The pressure of carbon dioxide gas is 11 atm

<u>Explanation:</u>

To calculate the pressure of gas, we use the equation given by ideal gas equation:

PV = nRT

where,

P = pressure of the gas = ?

V = Volume of gas = 25 L

n = number of moles of gas = 10 mole

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature of the gas = 325 K

Putting values in above equation, we get:

$P\times 25L=10mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 325K\\\\P=11atm$

Hence, the pressure of carbon dioxide gas is 11 atm

4 0

3 years ago

A student carries out a chemical reaction that produces a brown powder. How should the student measure the amount of product for

adoni [48]

The mass of the solid product of the reaction is determined by weighing.

6 0

3 years ago

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What is the concentration of a sodium hydroxide solution if 14.5 mL of it are exactly neutralized by 30.0 mL of a 0.500 M hydroc

rusak2 [61]

Answer:

1.03 M

Explanation:

Step 1: Write the balanced equation

NaOH + HCl ⇒ NaCl + H₂O

Step 2: Calculate the reacting moles of HCl

30.0 mL (0.0300 L) of 0.500 M HCl react.

0.0300 L × 0.500 mol/L = 0.0150 mol

Step 3: Calculate the moles of NaOH that react with 0.0150 moles of HCl

The molar ratio of NaOH to HCl is 1:1. The moles of NaOH that react are 1/1 × 0.0150 mol = 0.0150 mol.

Step 4: Calculate the molar concentration of NaOH

0.0150 moles of NaOH are in 14.5 mL (0.0145 L).

M = 0.0150 mol/0.0145 L = 1.03 M

4 0

3 years ago

A 155 g sample of an unknown substance was heated from 25°c to 40°c. in the process, the substance absorbed 569 calories of ener

Tasya [4]

Energy= 2381 joules
heat= Mass(kg) *change in temperature(K) * Cp
2381=0.155*(15)*Cp
Cp=1024 J/kg K

5 0

3 years ago

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